butterflies' methods questions thread

[butterflies]

hi, unfortunately my methods teacher is pathetic and does not explain anything. hence, our entire class is struggling in methods, and they mostly ask me for help. this is fine, when i understand what's going on, but sometimes i don't have a clue, either, and i thought it pertinent to make a thread of questions. for now i just have two, but this will probably increase as time goes on.

~~~

1.) tickets at a concert are available at two prices. the more expensive ticket is $30 more than the cheaper one. find the cost of each type of ticket if a group can buy 10 more of the cheaper tickets than the expensive ones for $1300.

2.) the members of a club hire a bus for $2100. seven members withdraw from the club and the remaining members have to pay $10 more each to cover the cost. how many members originally agreed to go on the bus?

thankyou in advance.

butterflies

[Mao]

1) Let cheaper tickets be x, the expensive tickets are x+30

At 1300, the group can buy 1300/x cheap tickets, and 1300/(x+30) expensive tickets. If the difference is 10, we thus arrive at

, solve for x.

2) Initially there are x members. The cost for each member is 2100/x. Now there are (x-7) members, the cost for each is 2100/(x-7). If this cost is $10 more than before, the equation is then

, solve for x.

[butterflies]

omg that's one way to make me feel silly -- it makes so much more sense now! thankyou!!!

=D

[luffy]

1) Let cheaper tickets be x, the expensive tickets are x+30

At 1300, the group can buy 1300/x cheap tickets, and 1300/(x+30) expensive tickets. If the difference is 10, we thus arrive at

, solve for x.

2) Initially there are x members. The cost for each member is 2100/x. Now there are (x-7) members, the cost for each is 2100/(x-7). If this cost is $10 more than before, the equation is then

, solve for x.

Wow.... nice work!! I can't believe I accidentally wrote a 'y + 30' instead of 'x + 30' - Far too many silly mistakes