help force Q

[Boots]

hey guys this is a first yr uni physics q
its pretty basic but i havent done physics in yr12 so i cant do it, if u cld help that wld be great

a cyclist rides up a steady slope for a distance of 1200m and rises 90m vertically as a result. the total mass of rider + cycle is 80kg
a) assume a drag force of 10N opposing the motion(due to air resistance and friction), what Total Work must be output by the rider for this climb?

[enpassant]

10x1200 + 80x9.8x90 J

[soopertaco]

10x1200 + 80x9.8x90 J

change in energy is equivalent to Work. So since there is a change in vertical height we can say that there is a change in gravitational potential energy: Mass * gravity * height

another formula for work is Force by distance thus: 10N * 1200m
add these to get there total

haha just thought i might add an explanation

[schnappy]

Work = [Work done against gravity] + [Work done against friction]
Work = [80*90g] + [10*1200]
Work = bleh

[Boots]

10x1200 + 80x9.8x90 J

change in energy is equivalent to Work. So since there is a change in vertical height we can say that there is a change in gravitational potential energy: Mass * gravity * height

another formula for work is Force by distance thus: 10N * 1200m
add these to get there total

haha just thought i might add an explanation

Thank you soo much I really appreciate it