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November 01, 2025, 03:09:45 pm

Author Topic: urgent! sac tomorrow :( - colinearity  (Read 639 times)  Share 

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soopertaco

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urgent! sac tomorrow :( - colinearity
« on: April 05, 2011, 08:02:11 pm »
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How do we prove three point are colinear, using three already defined position vectors

the question might ask show that a,b,c are colinear

i get as far as AB = nBC

then i find AB and BC but then im lost from there, how do i finish this off? or am i even doing it properly?
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jasoN-

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Re: urgent! sac tomorrow :( - colinearity
« Reply #1 on: April 05, 2011, 08:05:28 pm »
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AB = kBC that shows they're parallel
but u also need to show they share the same point
so in this case u just write both share point B or something
and thats colinear
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soopertaco

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Re: urgent! sac tomorrow :( - colinearity
« Reply #2 on: April 05, 2011, 09:25:37 pm »
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hey thanks for clarifying :)

just wondering, when finding average velocity over a time interval of say [0,10] (this is for vector calculus btw) is it
( v(10) - v (0) ) / (10)  ?
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jasoN-

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Re: urgent! sac tomorrow :( - colinearity
« Reply #3 on: April 05, 2011, 09:36:35 pm »
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average velocity =  displacement / time =
2009-10: Methods (39) - Specialist Maths (36) - Further Maths (50) - Biology (36) - Chemistry (37) - English Language (36) - ATAR: 97.40
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