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June 10, 2026, 10:37:40 am

Author Topic: ssNake's Chemistry [u2] Q's  (Read 41164 times)  Share 

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Re: ssNake's Chemistry [u2] Q's
« Reply #180 on: November 01, 2011, 11:01:01 am »
0
Yeah but WHY.

Zn --> Zn2+ + 2e

That occurs at the anode to produce excess +2 ions. Shouldn't the polarity be (+) - isn't this why anions flow from the salt bridge to the anode to counter the build up of + charge?
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Re: ssNake's Chemistry [u2] Q's
« Reply #181 on: November 01, 2011, 04:44:35 pm »
+1
I'm assuming you're still talking about 1/2 level stuff here: My teacher has told us not to memorise 'anode is negative, cathode is positive' as that is not always the case in some other kind of reaction we do in Unit 3/4.

Instead, he's told us the definition "the source of the electrons is always negative."

Going by this, the anode is the source, as this is where oxidation occurs - i.e. where the electrons are 'lost' and then travel to the cathode (where reduction occurs). 

That occurs at the anode to produce excess +2 ions. Shouldn't the polarity be (+) - isn't this why anions flow from the salt bridge to the anode to counter the build up of + charge?
Edit: sorry didn't notice there was another page.

The way I understand it is after the anode loses the electrons, it gains a positive charge. The anions from the salt bridge flow to neturalise this charge. The charge is no longer positive in the anion after it is neturalised (so the polarity wouldn't be +). It can then proceed to lose more electrons (source of electrons is negative blah blah blah) and thus the reaction continues? I presume all this would happen very quickly.
« Last Edit: November 01, 2011, 04:55:49 pm by laseredd »

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Re: ssNake's Chemistry [u2] Q's
« Reply #182 on: November 01, 2011, 05:24:11 pm »
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i like the definition your teacher gave you much more logical than memorising :D
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Re: ssNake's Chemistry [u2] Q's
« Reply #183 on: November 01, 2011, 08:27:41 pm »
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The equation with the higher E0 will be the +
The equation with the lower E0 will be the -

If it is a galvanic cell (or spontaneous redox reaction), electrons will flow from - to +
If it is an electrolytic cell, the electron flow is reversed
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Re: ssNake's Chemistry [u2] Q's
« Reply #184 on: November 01, 2011, 09:01:32 pm »
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No idea what EO is? Is that 3/4?
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Re: ssNake's Chemistry [u2] Q's
« Reply #185 on: November 01, 2011, 09:24:48 pm »
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No idea what EO is? Is that 3/4?
E-nought values. Each reaction thing in the electrochemical series has an associated value. It's the EMF that is produced for each metal when it reacts with the with a Hydrogen half-cell I think it was (can't quite recall exactly). That's what I understood from what I was told. There was something more about equilibrium and standard conditions, so it is Unit 3/4 stuff.

http://www.vcaa.vic.edu.au/vcaa/vce/exams/examcovers/Nov_2011_covers/2011chem2-cov.pdf - The databook lists it next to the electrochemical series. 

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Re: ssNake's Chemistry [u2] Q's
« Reply #186 on: November 02, 2011, 04:41:57 pm »
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What mass of calcium chloride must be dissolved in 250mL of deionised water to prepare an aqueous solution that has a chloride ion concentration of 0.12M?

----

If 150mL of 0.8M HCl is mixed with 50mL of 0.4M NaOH the pH of the resulting sol would be?
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Re: ssNake's Chemistry [u2] Q's
« Reply #187 on: November 02, 2011, 08:11:56 pm »
+1
What mass of calcium chloride must be dissolved in 250mL of deionised water to prepare an aqueous solution that has a chloride ion concentration of 0.12M?

----

If 150mL of 0.8M HCl is mixed with 50mL of 0.4M NaOH the pH of the resulting sol would be?

you want 0.12M.
so n(Cl-) = 0.12M x .25 = 0.03mol
but calcium chloride is CaCl2
so you need 0.015 mol of CaCl2
0.015 x 115 = 1.725g.

you have 0.15 x 0.8 = 0.12 mol of hydronium ions
.05 x 0.4 = 0.02 mol of hydroxide ions
when you reacted you're left with 0.1 mol of hydronium.
and then your mixture is 200ml
so 0.5M H3O+
and then yeah, -log10[H3O+]
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Re: ssNake's Chemistry [u2] Q's
« Reply #188 on: November 09, 2011, 05:03:46 pm »
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What would be the best appropriate answer relating to the Question attached and why?

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Re: ssNake's Chemistry [u2] Q's
« Reply #189 on: November 09, 2011, 05:07:38 pm »
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A because B, C and D are right...?

This is my q thread btw :p
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Re: ssNake's Chemistry [u2] Q's
« Reply #190 on: November 09, 2011, 05:10:04 pm »
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why is it A?

lol,:p sorry bro!

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Re: ssNake's Chemistry [u2] Q's
« Reply #191 on: November 09, 2011, 05:10:47 pm »
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No electrons are provided. Na+ and Cl- carry the charge and hence electricity.
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Re: ssNake's Chemistry [u2] Q's
« Reply #192 on: November 09, 2011, 05:12:15 pm »
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oh, ok, tnx!

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Re: ssNake's Chemistry [u2] Q's
« Reply #193 on: November 09, 2011, 05:15:57 pm »
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guys don't revise for chem....lets all start together after my spesh exam..
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Re: ssNake's Chemistry [u2] Q's
« Reply #194 on: November 09, 2011, 05:16:26 pm »
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dude, what about this one...

A 2.894g of calcium carbonate was added to 500.0 mL of 0.100M nitric acid and allowed to react. A the completion of the reaction, how many moles of nitric acids (and calcium carbonate) would remain?


When do we need to find the excess and limiting reagent when given a reaction?