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November 08, 2025, 05:19:33 am
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Tea.bag

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help
« on: November 06, 2008, 09:06:37 pm »
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whats the period of |3cos(2x)|?
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cinnamonbun

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Re: help
« Reply #1 on: November 06, 2008, 09:07:12 pm »
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pi/2 i think
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danieltennis

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Re: help
« Reply #2 on: November 06, 2008, 09:11:15 pm »
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Quote from: Tea.bag on November 06, 2008, 09:06:37 pm
whats the period of |3cos(2x)|?

Its just pi/2.
Edit:(opps)

« Last Edit: November 06, 2008, 09:16:58 pm by danieltennis »
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trinon

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Re: help
« Reply #3 on: November 06, 2008, 09:12:54 pm »
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cinnamonbun

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Re: help
« Reply #4 on: November 06, 2008, 09:15:22 pm »
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Quote from: danieltennis on November 06, 2008, 09:11:15 pm
Quote from: Tea.bag on November 06, 2008, 09:06:37 pm
whats the period of |3cos(2x)|?

Its just pi.

its pi on 2 cos wen u hav absolute function it reflects in the x axis right? so the period becomes half as the cycle is like halved.. try draw it xP
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spudman

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Re: help
« Reply #5 on: November 06, 2008, 09:19:27 pm »
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the what occurs when u get |3cos2x + 1|?
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cinnamonbun

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Re: help
« Reply #6 on: November 06, 2008, 09:20:32 pm »
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the period shood still be the same
edit: oh wait
no its not
 i have no idea wut the period wood be

edit: i think the period wood be pi XD
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Quickclaw

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Re: help
« Reply #7 on: November 06, 2008, 09:40:01 pm »
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wouldn't it stay the same because the only thing you are changing is reflecting the negative part of the graph, so it would be  ?
But on the other hand, the graph is repeating each interval which would define a period, so I actually go with lol
« Last Edit: November 06, 2008, 09:44:57 pm by Quickclaw »
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AppleXY

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Re: help
« Reply #8 on: November 06, 2008, 09:45:41 pm »
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Sorry,

Is it |3cos(2x) + 1| or |3cos(2x+1)|

it makes a big difference. :)
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Collin Li

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Re: help
« Reply #9 on: November 06, 2008, 10:53:51 pm »
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Quote from: AppleXY on November 06, 2008, 09:45:41 pm
Sorry,

Is it |3cos(2x) + 1| or |3cos(2x+1)|

it makes a big difference. :)

[Incorrect information]
« Last Edit: November 06, 2008, 11:08:42 pm by coblin »
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vce08

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Re: help
« Reply #10 on: November 06, 2008, 10:58:47 pm »
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Are you sure coblin?
Say the graph |3cos(2x) + 4|
That would have a period of pi,
Whilst the graph of |3cos(2x)| + 4 would have a graph of pi/2 right?
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onlyfknhuman

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Re: help
« Reply #11 on: November 06, 2008, 11:03:05 pm »
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edit: im wrong i follow collin :D
« Last Edit: November 06, 2008, 11:11:11 pm by onlyfknhuman »
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Collin Li

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Re: help
« Reply #12 on: November 06, 2008, 11:08:12 pm »
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Quote from: vce08 on November 06, 2008, 10:58:47 pm
Are you sure coblin?
Say the graph |3cos(2x) + 4|
That would have a period of pi,
Whilst the graph of |3cos(2x)| + 4 would have a graph of pi/2 right?
Quote from: onlyfknhuman on November 06, 2008, 11:03:05 pm
no both have a period of pi/2

translations do not affect period.

Actually, yeah I agree with vce08. The translation matters because the modulus has a special effect on the period in this case. It depends on the inside function being centered at zero.
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vce01

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Re: help
« Reply #13 on: November 06, 2008, 11:11:18 pm »
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shit, what effect does the absolute function have on the period? for sin/cos and tan? do you just find the normal period and times it by 1/2?
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Collin Li

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Re: help
« Reply #14 on: November 06, 2008, 11:14:02 pm »
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Imagine . That has a period of instead of because all of a sudden all the negative parts are reflected to become exactly the same as the positive parts.

However, doesn't have that same effect. It will still have some reflection, but it will not halve the period.
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