More Vector Proof Questions

[kaanonball]

The Question
ABCD is a parallelogram. M is the midpoint of AB. P is the point of trisection of MD nearer to M. Prove that A, P and C are collinear and that P is a point of trisection of AC.

At the moment I'm not sure how to get started with this question, mainly because I'm unsure how to represent P is the point of trisection of MD nearer to M on the Parallelogram.

Also if vectors are collinear, does that mean for instance A = mP = nC ?

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"P is the point of trisection of MD nearer to M on the Parallelogram."

This means that , or

If points A, P and C are collinear, you prove that



or



In general for 2 dimensions, collinear vectors must be dependent and share a point.

[kaanonball]

Oh ok, I get it now! Thanks. There's just one more thing how do I prove point P is the point of trisection?

[hamtarofreak]