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May 20, 2024, 04:12:37 pm

Author Topic: vcaa mc 2008 q20  (Read 635 times)  Share 

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qshyrn

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vcaa mc 2008 q20
« on: November 07, 2010, 07:35:28 pm »
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can some1 explain why fe2+ is a stronger reductant than br-

JinXi

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Re: vcaa mc 2008 q20
« Reply #1 on: November 07, 2010, 07:37:49 pm »
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Cause referring to the electrochemical series, reductants are on the left, increasing in reducing strength(better reductant) as they go down.

Find fe2+ and br- and you'll see that fe2+ is below Br-.


Edit: whoops reductants are on the right (i mean)... too much studying makes me dizzy..
« Last Edit: November 07, 2010, 07:40:30 pm by JinXi »
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jasoN-

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Re: vcaa mc 2008 q20
« Reply #2 on: November 07, 2010, 07:39:25 pm »
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reductants are on the right :P, but yes Fe2+ is lower than Br-, hence a stronger reductant
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qshyrn

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Re: vcaa mc 2008 q20
« Reply #3 on: November 07, 2010, 07:42:08 pm »
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isnt fe 2+ on the left? meaning its an oxidant, whereas Br- is on the right (its a reductatn)  ...
sorry havent studied chem in a  long long time

JinXi

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Re: vcaa mc 2008 q20
« Reply #4 on: November 07, 2010, 07:43:14 pm »
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isnt fe 2+ on the left? meaning its an oxidant, whereas Br- is on the right (its a reductatn)  ...
sorry havent studied chem in a  long long time

Fe2+ can act as an oxidant or reductant, hence the two equations involving fe2+ in the electrochemical series.
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qshyrn

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Re: vcaa mc 2008 q20
« Reply #5 on: November 07, 2010, 07:49:40 pm »
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isnt fe 2+ on the left? meaning its an oxidant, whereas Br- is on the right (its a reductatn)  ...
sorry havent studied chem in a  long long time

Fe2+ can act as an oxidant or reductant, hence the two equations involving fe2+ in the electrochemical series.
oooh ok

masonnnn

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Re: vcaa mc 2008 q20
« Reply #6 on: November 07, 2010, 08:03:57 pm »
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there's a few things like that(reductant and oxidant), Sn and H20 are as welll. have a general idea of that because while i don't know if they do in exams, in sacs/tests i've come across trick-type questions using them.
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