VCE Methods Question Thread!

[nyggfany]

Just like to add a little to the solution. If a + b is indeed zero, any value of x will solve the equation.

That's a pretty nasty equation you're asked to solve

Agree. It's a nasty question but also a really good one to practice some basic mathematical skills.
I'm currently working on some those which need to put more thoughts on. Here is one of them ():

[RuiAce]

Agree. It's a nasty question but also a really good one to practice some basic mathematical skills.
I'm currently working on some those which need to put more thoughts on. Here is one of them ():
(Image removed from quote.)

I gave that one a tiny bit of thought and ended up with this. Not sure if helpful.
I may look at it again later

Edit: Some playing around with WolframAlpha seems to have revealed something.
Note that the final line of what I wrote is a contradiction.

At one point in there I divided the v back out. Note that this assumes \(v\neq 0\). Checking v=0 reveals something...

[nyggfany]

I gave that one a tiny bit of thought and ended up with this. Not sure if helpful.(Image removed from quote.)
I may look at it again later

Yes. You've got the idea. But instead of letting x-1/x be u and 2x-5/x be v, it would be better if you let square root of (x-1/x) be u and square root of (2x-5/x) be v

[RuiAce]

Yes. You've got the idea. But instead of letting x-1/x be u and 2x-5/x be v, it would be better if you let square root of (x-1/x) be u and square root of (2x-5/x) be v

Yeah, that works and should be tidier. But I think I figured it out anyhow.

[peanut]

Thanks for that. So is that answer equivalent to the bottom one?

No, it is not. It is likely they performed an extra dilation of factor 1/3 from the x-axis. It's a textbook error, don't worry about it

[nyggfany]

Hey everyone,

I have attached two questions, which I am having a bit of trouble with.

For the first one, I don't understand where the 1/3 out the front comes from. The rest of the rule is fine.

For the second question (where I need to state a sequence of transformations that transforms the graph of the first equation into the graph of the second equation), I don't understand how the answer has been derived. I would appreciate an explanation.

Thanks in advance! 

Here's another way you can state the sequence of transformations (don't worry, it's equivalent to the solution but easier to understand )

[RuiAce]

Hey 
can someone find x in this figure here:
http://imgur.com/D2eyIMQ
Thanks!!

[vcestressed]

Thanks for your help! Idk why i couldnt get it - so simple 
Thanks again!

[wyzard]

Thanks for your help! Idk why i couldnt get it - so simple 
Thanks again!

Hindsight bias bro

Things always look so simple looking back, and it's common to say "I should have known!". It's perfectly normal, given the knowledge you had before you wouldn't be able to work it out That's the thing about math, very often after we figured it out, it seemed so obvious.

[Gogo14]

Help with this q.
The answer says x=0 or 1, but 0 is not in the domain?

[RuiAce]

Help with this q.
The answer says x=0 or 1, but 0 is not in the domain?

That's extremely bad.

Should be -1 or 1 if anything.

[wyzard]

Help with this q.
The answer says x=0 or 1, but 0 is not in the domain?

Should be -1 or 1, no way it can be 0 as it's undefined for either domains. Think they stuffed it up in the answers.

[cutiepie30]

How would you do this question attached . ( find values of a and b )

[Syndicate]

How would you do this question attached . ( find values of a and b )

98+a = 180, therefore a = 82
47+b =180, therefore b = 133

[Guideme]

(a+b)x+cy=bc
(b+c)y +ax=-ab
Solve x and y