In a large population of moths, the number of eggs per cluster is approximately normally distributed with a mean of 165 eggs and a standard deviation of 25 eggs.
Using the 68-95-99.7% rule determine
i. The percentage of clusters expected to contain more than 140 eggs
ii. the number of clusters expected to have less than 215 eggs in a sample of 1000 clusters
c. The standardized number of eggs in one cluster is given by z= -2.4
Determine the actual number of eggs in this cluster
hi
i. 140 = 165-25 = mean - standard deviation, mean - standard deviation is 16%, so more than 140 eggs is 84%, in other words (100%-16%)
ii. 215 = 165 + 2(25) = mean + 2*standard deviation = 2.5%, so 2.5% of 1000 = 25
so 1000-25 =
975c. standard score = (actual score - mean)/(standard deviation)
-2.4 = (actual score - 165)/(25)
(actual score - 165)/(25) = -2.4
(actual score - 165) = -60
actual score = -60+165
actual score = 105
Hope these answers help