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April 29, 2024, 06:47:06 pm

Author Topic: VECTOR angle!  (Read 393 times)  Share 

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poohead

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VECTOR angle!
« on: March 09, 2011, 06:12:35 pm »
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hey guys

how do i find the acute angle btw planes 2x+y-2z=5 3x-6y-2z=7??

I keep getting 70.89 degrees
but according to the book the answer is 79.0

:/

help please?

xZero

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Re: VECTOR angle!
« Reply #1 on: March 09, 2011, 06:33:59 pm »
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isn't this more like uni maths? but anyways the normal to the plane 1 is (2,1,-2) and the normal to the plane 2 is (3,-6,-2). The angle between the planes is the angle between the normals so use angle =cos^-1(dot product/the multiple of the two modulus) and you should get 79.02 degrees
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