A square pyramid has a volume of 25m^3 (with a height of 3m).
The square pyramid is filled with foam insulation to a depth of one metre.
What percentage of the original roof space is now filled with foam insulation? Write your answer correct to the nearest whole number.
Thank you
edit; height is actually 3m ._.
Firstly, find the length of one side of the base (Use 25m^3):
Volume of square base pyramid is 1/3 l^2 times its height: 1/3 x l^2 x 3 = 25
l^2 = 25
length = 5 metres
Now, use ratios to find the length of one side, where the foam reaches 1 metre: Small : Large Small : Large
length ratio: x : 5 = 2 : 3
x/5 = 2/3
x = 2/3 x 5
x = 10/3 (leave this as a fraction for more accurate results)
Now find the volume of the smaller square base pyramid on top. Because the foam reaches 1 metre, the height of the top pyramid is 3-1= 2 metres. Use this to find its volume: V= 1/3 x (10/3)^2 x 2 = 7.4 metres^3 approx.
From the initial 25 m^3, take away the 7.4m^3 to get the volume of the bottom half of the pyramid (which is what you want- with the foam insulation): 25-7.4= 17.6 metres cubed
Finally, put this value over the original volume and multiply by 100 to get the volume that the roof space is filled with insulation. That is,
17.6/ 25 x 100= 70.4%
BUT WRITE ANSWER TO THE NEAREST WHOLE NUMBER. Hence, 70% ! Hope this is correct