VCE General & Further Maths Question Thread!

[Cort]

Hey guys 2012 Exam 2 , Question 2B about some stupid weather LOl here is the question

(Image removed from quote.)

Question B

Hope it wasn't too confusing. I didn't even understand the question at all the first time I did it.

[lolipopper]

Business Maths question:

Question 7:
Greta and Sean have taken out a reducing balance loan of $340 000 at a fixed interest rate of 9% per annum calculated monthly. They make monthly repayments of $P so that in 5 years time they will owe just $80 000 on their loan.
The value of P is

A.   7 057.84
B.   8 118.51
C.   10 382.01
D.   11 024.84
E.   36 129.62

Suggested Answer:
Using TVM solver we have
N=60
I%=9
PV=340,000
PMT=?
FV=80,000
P/Y=12
C/Y=12
Their monthly payment is $8 118.51 therefore B.

My concern: should not the FV (amount owing) be -80,000 when put into TVM? Im getting $5996.17

[tcstudent]

Hope it wasn't too confusing. I didn't even understand the question at all the first time I did it.

yea man for me very confusion, it must be due to me being overwhelmed by exams.

[Yacoubb]

Hey guys 2012 Exam 2 , Question 2B about some stupid weather LOl here is the question

(Image removed from quote.)

Question B

The first thing you're told is that there are 8 wind speeds.

We know that Q1 = min (in this case) =2
We know that Q3 = max(in this case) = 4

So, you get:

2, __, __, __, __, __, __, 4.

Then, we're told the median is 3.5. Because we have 8 values, the position of the median will be the 4.5th. That is, the average of the 4th and 5th value should equal the median, which in this case is 3.5. So, if 3+4/2 = 3.5, we can fairy say that term 4= 3 and term 5=4.

So:

2, __, __, 3, 4, ___, __, 4.

Now, you know that your Q1 = 2.
So, your (2nd + 3rd term)/2 = 2.
Thus, 2+2/2 = 2. So terms 2 and 3 are 2.

So:

2, 2, 2, 3, 4, __, __, 4.

Now, Q3 is 4.
4+4/2 = 4. Hence, terms 6 and 7 are 4.

Your answer:

2, 2, 2, 3, 4, 4, 4, 4.

^ Hope this helped.

To check, I'd put those data entries into my calculator & construct a boxplot, from which I'd then check to see whether I was right or wrong.

[duhherro]

Btw guys for Business maths Q3)c)ii) on exam 2 of 2012... is it a perpetuity question? I just treated it continuing the previous question, so there would be 4 years left to pay it all up .

[Daenerys Targaryen]

You get your regression line by what ever means, and use that equation. Then sub in 370, then 201 and so on. And you just solve for the rate - which is rate i assume

[popoy111]

I am currently doing business related maths. I own both textbooks of MAths quest and essentials but i find maths quest to be way to long. Just want to know which one you think addresses business related mathematics better?

[Zealous]

I am currently doing business related maths. I own both textbooks of MAths quest and essentials but i find maths quest to be way to long. Just want to know which one you think addresses business related mathematics better?

Isn't Business Maths in Maths Quest like ... 2 chapters? I don't think it is extremely long, just plan out how much you want to do when, and you should get it done.

If your school uses Maths Quest for a textbook, it might be worth sticking to it as your teachers might be more accustomed to using that textbook if you end up requiring assistance. Also, Maths Quest seems to be better for the theory and concept stuff, while Essentials may provide harder questions.

[darklight]

Hi guys, when a question asks to plot the values, do you just put the points on the graph or do you drew a line through them?

[Thorium]

Hi guys, when a question asks to plot the values, do you just put the points on the graph or do you drew a line through them?

For a scatter plot, you only put the values on the graph. You fit a regression line on the graph when they ask you to "fit a regression line on the graph".

[darklight]

For a scatter plot, you only put the values on the graph. You fit a regression line on the graph when they ask you to "fit a regression line on the graph".

Thanks but I meant for Module 3, Graphs and Relations!

[spectroscopy]

Is there a way to find out when a matrix becomes a steady state??
as S1=TSo and S3=t^3 So    and thus Sn=T^n So
is there a way to find out at what value of n the steady state appears?

[Einstein]

why is the answer C? i square rooted the answer and it doesn't work because then you need imaginary numbers, so i took the square root and i got E

[Thorium]

Is there a way to find out when a matrix becomes a steady state??
as S1=TSo and S3=t^3 So    and thus Sn=T^n So
is there a way to find out at what value of n the steady state appears?

For this we use the "trial and error method"
You have to show that two-three consecutive values of n yield a steady result, then the ans will be the initial value of n.

^Using my phone, so cant show a proper example. Hope it helps

[kinslayer]

why is the answer C? i square rooted the answer and it doesn't work because then you need imaginary numbers, so i took the square root and i got E

The coefficient of determination is r^2. You are given r, so square it (find r^2) and pick the option that matches.