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April 28, 2024, 09:47:31 am

Author Topic: VCE General & Further Maths Question Thread!  (Read 759270 times)  Share 

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Mellyboo

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Re: VCE Further Maths Question Thread!
« Reply #900 on: January 29, 2015, 10:11:23 pm »
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Make sure you don't tab the pages. I was told that as long as they can't be removed that I could have them. Unfortunately, they wouldn't have any of that and I was forced to cut mine off, minutes before go time.  >:(
« Last Edit: January 29, 2015, 10:13:14 pm by Mellyboo »
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Orson

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Re: VCE Further Maths Question Thread!
« Reply #901 on: February 09, 2015, 06:21:39 pm »
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A table of values for against is as shown.


Given that , find values of and .

Thanks!
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keltingmeith

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Re: VCE Further Maths Question Thread!
« Reply #902 on: February 10, 2015, 02:08:35 am »
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A table of values for against is as shown.


Given that , find values of and .

Thanks!

When y=4.2, x=1, so:

y=kx^n ===> 4.2=k(1^n) ===> k=4.2

Welp, that was easy. Now, when x=2, y=33.6:

33.6=4.2(2^n) ===> 2^n=8 ===> 2^n=2^3 ===> n=3

So, n=3 and k=4.2
Note that the last step might prove tricky for the average Further student - solving 33.6=4.2(2^n) with a CAS is absolutely fine. You could also solve it using a simultaneous equation solver on your CAS, but mine didn't like that for whatever reason, so you might get a similar issue.

Orson

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Re: VCE Further Maths Question Thread!
« Reply #903 on: February 11, 2015, 02:03:02 pm »
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When y=4.2, x=1, so:

y=kx^n ===> 4.2=k(1^n) ===> k=4.2

Welp, that was easy. Now, when x=2, y=33.6:

33.6=4.2(2^n) ===> 2^n=8 ===> 2^n=2^3 ===> n=3

So, n=3 and k=4.2
Note that the last step might prove tricky for the average Further student - solving 33.6=4.2(2^n) with a CAS is absolutely fine. You could also solve it using a simultaneous equation solver on your CAS, but mine didn't like that for whatever reason, so you might get a similar issue.

Yea thanks. I tried to do simultaneous equations on my CAS but I got an "argument error". Cheers.
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AngelWings

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Re: VCE Further Maths Question Thread!
« Reply #904 on: February 11, 2015, 11:55:08 pm »
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Make sure you don't tab the pages. I was told that as long as they can't be removed that I could have them. Unfortunately, they wouldn't have any of that and I was forced to cut mine off, minutes before go time.  >:(

That's actually incorrect. You can have them as long as it:
So, if you have a page cut a sliver (that's the size of the tab - so probably an inch or so) to add the permanent tab, that's actually fine. It's also fine if you cut your A4 sheets down, so that the side is your tab or cutting corners for a "layered" effect. Colour-coding's good too, provided it follows the rules on the link above.

I did the bottom right one last year and that was absolutely fine. To show you what's allowed visually, see the attached image.
Spoiler
For people who don't have 20-20 vision, the sheets say:
  • Top left: Your average sheet of paper
  • Top right: The cut corner (+ highlight) for layered effect
  • Bottom left: The cutout tab
  • Bottom right: The measured cut with permanent sticky tab (The yellow sheet's the sticky tab.)
You probably can't see it, but I've actually ruled lines and cut them, so the page is still A4 when closed.

The sticky tabs I've got here are kind of like labels, but 'fold-able' tab version (see image).
« Last Edit: February 13, 2015, 12:53:56 pm by AngelWings »
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aaziz17

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Re: VCE Further Maths Question Thread!
« Reply #905 on: February 12, 2015, 08:01:12 pm »
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Keep getting C answers says D can someone explain
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Cogglesnatch Cuttlefish

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Re: VCE Further Maths Question Thread!
« Reply #906 on: February 12, 2015, 08:35:18 pm »
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Keep getting C answers says D can someone explain
Spotted:
Striped:
So the question is asking for the year when the number of striped is twice the number of spotted. Thus, equate them as so:

Solve for n;
« Last Edit: February 12, 2015, 09:38:31 pm by Cogglesnatch Cuttlefish »
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aaziz17

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Re: VCE Further Maths Question Thread!
« Reply #907 on: February 12, 2015, 09:55:11 pm »
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Spotted:
Striped:
So the question is asking for the year when the number of striped is twice the number of spotted. Thus, equate them as so:

Solve for n;
i was using the sum equation thats why i  was a bit confused. Cheers for clearing that up for me
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Cosec

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Re: VCE Further Maths Question Thread!
« Reply #908 on: February 15, 2015, 06:16:54 pm »
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Can somebody answer this in a SAC style answer so i know whats required.
When is it not appropriate to set up an Ordered Stem and Leaf Plot for a data set?

keltingmeith

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Re: VCE Further Maths Question Thread!
« Reply #909 on: February 15, 2015, 06:32:55 pm »
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Can somebody answer this in a SAC style answer so i know whats required.
When is it not appropriate to set up an Ordered Stem and Leaf Plot for a data set?
When the data isn't numerical.

Cosec

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Re: VCE Further Maths Question Thread!
« Reply #910 on: February 15, 2015, 06:34:16 pm »
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When the data isn't numerical.

 How reliable are these z scores for interpretive purposes?

keltingmeith

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Re: VCE Further Maths Question Thread!
« Reply #911 on: February 15, 2015, 08:28:17 pm »
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How reliable are these z scores for interpretive purposes?

A z score will tell you how many standard deviations away from the mean something is, from this you can use the 68-95-99.7% rule to discuss the reliability of the statistic/whether that piece of data is "normal", etc.

Cosec

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Re: VCE Further Maths Question Thread!
« Reply #912 on: February 16, 2015, 08:07:19 pm »
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Can someone confirm the skewness of these two box plots for me?
And is the outlier included in the range? Or do i do two ranges in my report. one with the outlier and one without?

Image:  http://imgur.com/dnZEKnc

Davos

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Re: VCE Further Maths Question Thread!
« Reply #913 on: February 16, 2015, 10:08:32 pm »
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I believe the first box plot is positively skewed because most of the data is found at the beginning of the plot. The second box plot should be approximately symmetrical as the data is evenly distributed throughout the plot. The outlier is included in the range calculations

Cosec

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Re: VCE Further Maths Question Thread!
« Reply #914 on: February 16, 2015, 10:21:06 pm »
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I believe the first box plot is positively skewed because most of the data is found at the beginning of the plot. The second box plot should be approximately symmetrical as the data is evenly distributed throughout the plot. The outlier is included in the range calculations

Would the first (blue) one be negatively skewed, how so would it be positively skewed?