VCE General & Further Maths Question Thread!

[Berimbolo King]

yeah that does make sense!
thank you so much 

Youre welcome 

[Escobar]

if a (1/y) transformation is done, and y=mx+c becomes 1/y=mx+c, is "1/y" now called the dependant variable? (instead of y)
something very similar to this came up heffernan 2015 prac exam 2 & the dependant variable was called 1/y

[Peanut Butter]

if a (1/y) transformation is done, and y=mx+c becomes 1/y=mx+c, is "1/y" now called the dependant variable? (instead of y)
something very similar to this came up heffernan 2015 prac exam 2 & the dependant variable was called 1/y

I recently completed this exam however my school is marking it for us so I haven't got the solutions yet.

I wrote 1/y as my answer.

This was my reasoning: a dependent variable is defined as the variable that is measured. Since in this instant you were measuring 1/y not just y, it is considered the dependent variable. Does that make sense?

[Escobar]

I recently completed this exam however my school is marking it for us so I haven't got the solutions yet.

I wrote 1/y as my answer.

This was my reasoning: a dependent variable is defined as the variable that is measured. Since in this instant you were measuring 1/y not just y, it is considered the dependent variable. Does that make sense?

yep, thanks

another question
if something is 'one and a half times bigger than' something else, is it 1.5x the size or 2.5x the size
i think it is 2.5x but heffernan thinks 1.5x

[Peanut Butter]

yep, thanks

another question
if something is 'one and a half times bigger than' something else, is it 1.5x the size or 2.5x the size
i think it is 2.5x but heffernan thinks 1.5x

I completely understand where you got your answer. I think the wording of the question is a bit funky (company papers are always like this hahaha)!

I'm not entirely sure... but I certainly don't see how you're wrong. Since the question said 1.5 times BIGGER (and not 'the size') I think you're right

[Escobar]

Why is option D wrong?
in the solution, it says that you can only say 49% of the variation of the dependant variable is explained by variation in the independant variable but doesn't this work the other way around as well?

[Escobar]

also,
how are we supposed to know these transformations? my textbook has a list of transformations & when to apply them but some of these are not in there...
is this likely to come up in an exam 1? (this is from MAV)

[MightyBeh]

Why is option D wrong?
in the solution, it says that you can only say 49% of the variation of the dependant variable is explained by variation in the independant variable but doesn't this work the other way around as well?

It doesn't work both ways, it's a bit like working out the gradient with 'run' over 'rise' instead the standard 'rise'/'run'.

also,
how are we supposed to know these transformations? my textbook has a list of transformations & when to apply them but some of these are not in there...

Looks like a pretty standard circle of transformations question to me? Does your textbook have all of these?

is this likely to come up in an exam 1? (this is from MAV)

Probably not, but it's good to know anyway. 

[RazzMeTazz]

For Question 2.b) I was wondering, how do you know the two triangles given are similar triangles (Although the question doesnt really ask for this).

Also how would you solve question 2.d)

Thanks

[MightyBeh]

The triangles in 2b. are similar because of the markings on the lines - I believe triangles indicate they're parallel, and short dashes indicate that they're the same length. Having two parallel lines means you 'know' that two angles are equal, and by extension you can find out the value of the third.

As for 2d., the second triangle has been rotated and flipped. After you notice, it's pretty simply:

[_fruitcake_]

also,
how are we supposed to know these transformations? my textbook has a list of transformations & when to apply them but some of these are not in there...
is this likely to come up in an exam 1? (this is from MAV)

It comes up sometimes. Vcaa like putting these in the exam 2 as 5 markers often, but u never know it could be in the exam 1 this year. Grab off all the transformations, stick it in your book, its better safe than sorry.

I had useless crap in my summary book, such as when something is already inversed, to get it out of inverse u simply inverse it again. The 2015 mav prac exam had that

[RazzMeTazz]

Thankyou for your help MightyBeh!

Could someone please help me on how to do the following attached question? Thanks!

[MightyBeh]

Thankyou for your help MightyBeh!

Could someone please help me on how to do the following attached question? Thanks!

Is the answer D? I'm pretty sure it can't be any of the answers with a 4 in it because that triangle isn't similar to any of the others (as far as I can tell, anyway).

Not confident on that though, I got a different (but pretty similar) answer when I did it myself.

Answer is A, if someone else doesn't I'll add working out later

[BakedDwarf]

Thankyou for your help MightyBeh!

Could someone please help me on how to do the following attached question? Thanks!

Uhh is the answer A? If that's right i'll post the working out.

[@#035;3]

Yep thats what I thought too A...