HINT: The velocity isn't constant due to the changing direction of the car.....remember velocity is a vector quantity......hence both magnitude (speed) and direction have to be constant for constant velocity
Yeah I know but its asking for magnitude, so the direction is not needed...the answer is 30500kgm/s
You need to consider the directions at first though.
Solution;
The car moves from B to A.
At B, the car is moving south. At A, the car is moving east. The magnitude of both momenta is the same (1200kg x 18ms-1 = 21600kgms-1), but the directions are different.
Looks like we need a triangle. We want the *change* in momentum from B to A - that is, the difference; "B - A" as it were. You should know how to do addition of basic vectors; to subtract the second from the first, merely reverse the direction of the second (that is, the direction at B).
We have a right triangle, with both sides being 21,600kgms-1. The magnitude of the momentum change will be the hypotenuse. Let's find that using pythagoras.
h^2 = 21,600^2 + 21,600^2 = 933,120,000
h = change in momentum = sqrt(933120000) = 30,547kgms-1 = 30,500kgms-1
Sorry if this is a bit unclear - it's hard explaining solutions like this (i.e., involving geometry) over the internet haha
EDIT: Whoops, did B-->A instead of A-->B. Same solution though.