Thanks.
But for Q4, im still confused. Wouldn't there only be a smaller titre if the standard solution was acidic and the unknown solution was basic?
If the standard solution was basic, the deionised water dilute it so it would require a greater titre if the unknown solution was acidic?
The pipette is rinsed deionised water, hence the aliquot will be diluted (so the solution with the known volume), hence it will have a lower concentration. The titre will be lower in value no matter it being an acid or a base.
c = n/v. So the lower the titre value, the higher the determined concentration of the unknown solution.
I think you are misinterpreting between what is a standard solution and titrant. The standard solution is the one being pipetted into an aliquot (it has a known concentration), whereas titrant is the one which has the unknown volume. You would be correct only if the titrant was diluted (this is the one placed in the burette), because then there would be a greater titre value.