Login

Welcome, Guest. Please login or register.

May 05, 2024, 01:10:19 am

Author Topic: dcc help me thread  (Read 22073 times)  Share 

0 Members and 1 Guest are viewing this topic.

unknown id

  • Victorian
  • Trendsetter
  • **
  • Posts: 131
  • Respect: +1
Re: dcc help me thread
« Reply #15 on: March 01, 2008, 09:46:30 pm »
0
oh, sorry droodles. I didn't know you only wanted hints on how to do the question.
« Last Edit: March 01, 2008, 11:22:39 pm by unknown id »
VCE Outline:
2007:   Accounting [48]

2008:   English [44], Maths Methods [50], Specialist Maths [41], Chemistry [50], Physics [44]

ENTER: 99.70





droodles

  • Guest
Re: dcc help me thread
« Reply #16 on: March 15, 2008, 08:34:11 pm »
0
divided by

there has to be another way of doing this besides manual long division.

sisqo1111

  • Victorian
  • Forum Leader
  • ****
  • Posts: 645
  • Respect: +1
Re: dcc help me thread
« Reply #17 on: March 15, 2008, 09:00:51 pm »
0
yep i know there is another way

cara.mel

  • Guest
Re: dcc help me thread
« Reply #18 on: March 15, 2008, 09:07:36 pm »
0
Manual long division, just because it's the only way I know and it gets you the answer anyway:
                                 x^2  - 9x + 27
x^2 - 2 | x^4 - 9x^3 + 25x^2 - 8x - 2
             x^4 + 0x^3 - 2x^2
                     -9x^3 + 27x^2 - 8x - 2
                     -9x^3 + 0x^2  + 18x
                                 27x^2 - 26x - 2
                                 27x^2 +0x   - 54
                                           - 26x + 52

=> x^2 -9x + 27 - (26x + 52)/(x^2-2)
« Last Edit: March 15, 2008, 09:10:19 pm by caramel »

dcc

  • Victorian
  • Part of the furniture
  • *****
  • Posts: 1198
  • Respect: +55
  • School Grad Year: 2008
Re: dcc help me thread
« Reply #19 on: March 15, 2008, 09:09:03 pm »
0
              x^2 - 9x + 27
x^2 - 2 | x^4 - 9x^3 + 25x^2 - 8x - 2
            -(x^4           - 2x^2)
                    - 9x^3 + 27x^2
                  -(- 9x^3          + 18x)
                                 27x^2 - 26x - 2
                               -(27x^2         - 54)
                                          -26x + 52



                               

Collin Li

  • VCE Tutor
  • Victorian
  • ATAR Notes Legend
  • *******
  • Posts: 4957
  • Respect: +17
Re: dcc help me thread
« Reply #20 on: March 15, 2008, 10:55:22 pm »
0
Synthetic division works too, but you have to store a term in your head in limbo for more than one step (you've gotta hold the term that has the lower degree for two rounds of division, if you know what I mean).

droodles

  • Guest
Re: dcc help me thread
« Reply #21 on: March 21, 2008, 07:47:09 pm »
0


Where am I looking to find the range of the function f(x)?

Mao

  • CH41RMN
  • Honorary Moderator
  • Great Wonder of ATAR Notes
  • *******
  • Posts: 9181
  • Respect: +390
  • School: Kambrya College
  • School Grad Year: 2008
Re: dcc help me thread
« Reply #22 on: March 21, 2008, 08:51:33 pm »
0
droodles try to find the lowest point for and the lowest point for =D
Editor for ATARNotes Chemistry study guides.

VCE 2008 | Monash BSc (Chem., Appl. Math.) 2009-2011 | UoM BScHon (Chem.) 2012 | UoM PhD (Chem.) 2013-2015

droodles

  • Guest
Re: dcc help me thread
« Reply #23 on: March 25, 2008, 12:01:19 am »
0
with a Domain of R / (1/2)

find f o f(x)

answer is f o f(x) = x but I end up cancelling the x's all the time!
« Last Edit: March 25, 2008, 12:05:15 am by droodles »

dcc

  • Victorian
  • Part of the furniture
  • *****
  • Posts: 1198
  • Respect: +55
  • School Grad Year: 2008
Re: dcc help me thread
« Reply #24 on: March 25, 2008, 12:10:28 am »
0











droodles

  • Guest
Re: dcc help me thread
« Reply #25 on: March 25, 2008, 12:16:23 am »
0
yeah i have but i've never come across a question like that, thanks bec tu sais tu es le meilleur ma choupette je t'aime fort

AppleXY

  • Life cannot be Delta Hedged.
  • Victorian
  • ATAR Notes Superstar
  • ******
  • Posts: 2619
  • Even when the bears bite, confidence never dies.
  • Respect: +16
Re: dcc help me thread
« Reply #26 on: March 25, 2008, 02:22:12 pm »
0
divided by

there has to be another way of doing this besides manual long division.

You also could use equality of polynomials as an alternative to Polynomial Division.

2009 - BBus (Econometrics/Economics&Fin) @ Monash


For Email: click here

Need a question answered? Merspi it!

[quote="Benjamin F

droodles

  • Guest
Re: dcc help me thread
« Reply #27 on: March 25, 2008, 04:31:24 pm »
0
e.g. ?

Mao

  • CH41RMN
  • Honorary Moderator
  • Great Wonder of ATAR Notes
  • *******
  • Posts: 9181
  • Respect: +390
  • School: Kambrya College
  • School Grad Year: 2008
Re: dcc help me thread
« Reply #28 on: March 25, 2008, 08:24:06 pm »
0
you probably just added something wrong droodles...
f o f(x) is always x, so you don't need to go through all the working out for that kind of thing...

have you done inverse functions yet?

i think  f o f(x) means "what does y equal when x=y" (if we call f(x) "y")
if x=y, it makes sense that y=x

(i think that's right! tell me if i'm wrong, anyone...)

umm... wot?

is applying f(x) twice, like , so only in rare cases does

such as if , then



divided by

there has to be another way of doing this besides manual long division.

You also could use equality of polynomials as an alternative to Polynomial Division.

how so.... there is a remainder in this case, it'll be very tricky...

but where given a factor and a polynomial , you could set up the quotient such that



expanding that with create two equal polynomials, where the coefficients are the same, with this you can find a,b,...
« Last Edit: March 25, 2008, 08:40:11 pm by Mao »
Editor for ATARNotes Chemistry study guides.

VCE 2008 | Monash BSc (Chem., Appl. Math.) 2009-2011 | UoM BScHon (Chem.) 2012 | UoM PhD (Chem.) 2013-2015

brendan

  • Guest
Re: dcc help me thread
« Reply #29 on: March 25, 2008, 08:56:11 pm »
0
in rare cases does

any examples?