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May 20, 2024, 05:57:41 pm

Author Topic: VCAA 2007 Q.  (Read 356 times)  Share 

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Slumdawg

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VCAA 2007 Q.
« on: November 07, 2010, 03:51:02 pm »
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Need some help. Could someone please show working for the following, assessor's reports answers are wayyy too brief.

Thanks.
2010 ATAR: 98.35 - Psychology [50] Media Studies [47
2011-'13: Bachelor of Biomedicine [Neuroscience Major] at Melbourne Uni 
2014-'17: Doctor of Medicine (MD) at Melbourne Uni 


ajjones

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Re: VCAA 2007 Q.
« Reply #1 on: November 07, 2010, 04:10:53 pm »
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find the equation of the graph |f(x)-g(x)| and then just solve to find the Maximum turning points like you normally would.

|f(x)-g(x)| = |6sin(xpi/2) -2(x^3 -6x^2 +8x)|
type this into y1 and graph it for the domain 0 to 4
there are 4 TP's and two of them are obviously higher than the others, use calc to find maximums and you get y= 1.08 at both x= 0.38 and x-3.62

Slumdawg

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Re: VCAA 2007 Q.
« Reply #2 on: November 07, 2010, 04:18:19 pm »
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find the equation of the graph |f(x)-g(x)| and then just solve to find the Maximum turning points like you normally would.

|f(x)-g(x)| = |6sin(xpi/2) -2(x^3 -6x^2 +8x)|
type this into y1 and graph it for the domain 0 to 4
there are 4 TP's and two of them are obviously higher than the others, use calc to find maximums and you get y= 1.08 at both x= 0.38 and x-3.62
ohhhhhhh. I was trying to find the turning points first each THEN minus them. Thanks.
2010 ATAR: 98.35 - Psychology [50] Media Studies [47
2011-'13: Bachelor of Biomedicine [Neuroscience Major] at Melbourne Uni 
2014-'17: Doctor of Medicine (MD) at Melbourne Uni