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May 06, 2024, 08:32:03 am

Poll

AFTER, reading this post, which response do you think is most correct?

A
B
C
D
this question will be cancelled/ everyone will get a mart (this is not an OPINION, there is no SHOULD, merely a WILL) so only select this question if u think the question WILLL be canceled not SHOULD be cancelled. VCAA thinks differently to us/the sane pe

Author Topic: MCQ 19  (Read 13409 times)  Share 

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Studyinghard

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MCQ 19
« on: November 11, 2010, 01:17:11 pm »
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I think just skip to question 19, thats where the argument is at.




Moderator Note: I have merged the discussion on this question from three different threads into this. The poll has been preserved. Pages 3/4/5 have the most recent discussion. - Mao
« Last Edit: November 13, 2010, 08:06:00 pm by Mao »
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Mao

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Re: MCQ 19
« Reply #1 on: November 11, 2010, 01:21:09 pm »
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I think just skip to question 19, thats where the argument is at.

I would say C. Electrons go from reductant (inside the compound) to the anode (onto the electrode) to the cathode (through wires) to the oxidant (to the chemical).

The other options are definitely wrong.
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Studyinghard

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Re: MCQ 19
« Reply #2 on: November 11, 2010, 01:22:16 pm »
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I think just skip to question 19, thats where the argument is at.

I would say C. Electrons go from reductant (inside the compound) to the anode (onto the electrode) to the cathode (through wires) to the oxidant (to the chemical).

The other options are definitely wrong.

fml ><
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Re: MCQ 19
« Reply #3 on: November 11, 2010, 01:22:51 pm »
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I think just skip to question 19, thats where the argument is at.

I would say C. Electrons go from reductant (inside the compound) to the anode (onto the electrode) to the cathode (through wires) to the oxidant (to the chemical).

The other options are definitely wrong.

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bomb

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Re: MCQ 19
« Reply #4 on: November 11, 2010, 01:25:36 pm »
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I think just skip to question 19, thats where the argument is at.

I would say C. Electrons go from reductant (inside the compound) to the anode (onto the electrode) to the cathode (through wires) to the oxidant (to the chemical).

The other options are definitely wrong.

i love you mao.

+10000
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Studyinghard

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Re: MCQ 19
« Reply #5 on: November 11, 2010, 01:27:16 pm »
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I still think C is worded incorrectly and yes im trying to argue so it makes me feel better.

For eg:
In a reaction of Cu2+ ions and Fe (s)

Here we would say that Fe(s) is the reductant right? and also the anode?
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physics

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Re: MCQ 19
« Reply #6 on: November 11, 2010, 01:29:31 pm »
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i think i should get a mark anyway :P
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vexx

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Re: MCQ 19
« Reply #7 on: November 11, 2010, 01:35:12 pm »
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I still think C is worded incorrectly and yes im trying to argue so it makes me feel better.

For eg:
In a reaction of Cu2+ ions and Fe (s)

Here we would say that Fe(s) is the reductant right? and also the anode?

yes this is what i think too, the reductant=anode..

edit, i think i get it now, this in a cell so there is an anode, so it could be metal Fe(s) but the reductant may be ions of something, that passes itself to the anode.. eeek, why did i not think this through!
« Last Edit: November 11, 2010, 01:39:04 pm by vexx »
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Mao

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Re: MCQ 19
« Reply #8 on: November 11, 2010, 01:39:57 pm »
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I still think C is worded incorrectly and yes im trying to argue so it makes me feel better.

For eg:
In a reaction of Cu2+ ions and Fe (s)

Here we would say that Fe(s) is the reductant right? and also the anode?

yes this is what i think too, the reductant=anode..

Yes, that is correct. However, it will still (to some extent), flow from the 'surface' of the electrode to the 'center' of the electrode as the reaction occurs. The electrode here implies something that conducts charges, whether or not it is also the reductant does not change the fact that the 'reacting' part of the electrode gives electrons to the 'conducting' part of the electrode.

I would however like to hear your justification for another option(s). I probably haven't considered it fully.
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Re: MCQ 19
« Reply #9 on: November 11, 2010, 01:40:13 pm »
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I think just skip to question 19, thats where the argument is at.

I would say C. Electrons go from reductant (inside the compound) to the anode (onto the electrode) to the cathode (through wires) to the oxidant (to the chemical).

The other options are definitely wrong.
YAYY! :) ahh well got tonnes of other crap wrong anyway. >.<

vexx

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Re: MCQ 19
« Reply #10 on: November 11, 2010, 01:42:07 pm »
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I still think C is worded incorrectly and yes im trying to argue so it makes me feel better.

For eg:
In a reaction of Cu2+ ions and Fe (s)

Here we would say that Fe(s) is the reductant right? and also the anode?

yes this is what i think too, the reductant=anode..

Yes, that is correct. However, it will still (to some extent), flow from the 'surface' of the electrode to the 'center' of the electrode as the reaction occurs. The electrode here implies something that conducts charges, whether or not it is also the reductant does not change the fact that the 'reacting' part of the electrode gives electrons to the 'conducting' part of the electrode.

I would however like to hear your justification for another option(s). I probably haven't considered it fully.

i just realised before, but thanks clear explanation
it's obviously not the others you are right, i picked A - wasn't thinking, since one doesn't store the reactants, rather they are supplied (for a fuel cell). silly me.
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Re: MCQ 19
« Reply #11 on: November 11, 2010, 01:49:26 pm »
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I still think C is worded incorrectly and yes im trying to argue so it makes me feel better.

For eg:
In a reaction of Cu2+ ions and Fe (s)

Here we would say that Fe(s) is the reductant right? and also the anode?

yes this is what i think too, the reductant=anode..

Yes, that is correct. However, it will still (to some extent), flow from the 'surface' of the electrode to the 'center' of the electrode as the reaction occurs. The electrode here implies something that conducts charges, whether or not it is also the reductant does not change the fact that the 'reacting' part of the electrode gives electrons to the 'conducting' part of the electrode.

I would however like to hear your justification for another option(s). I probably haven't considered it fully.

in a number of practice exams i did, fuel cells were siad to be rechargable, however this was not often done in practice.... why would vcaa ask a question that requires students to know that electrons flow from one part of the electrode to another... dno, i dont think they'll accept two answers, but searching on th enet it also states that fuel cells can be recharged....
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Re: MCQ 19
« Reply #12 on: November 11, 2010, 01:50:43 pm »
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I still think C is worded incorrectly and yes im trying to argue so it makes me feel better.

For eg:
In a reaction of Cu2+ ions and Fe (s)

Here we would say that Fe(s) is the reductant right? and also the anode?

yes this is what i think too, the reductant=anode..

Yes, that is correct. However, it will still (to some extent), flow from the 'surface' of the electrode to the 'center' of the electrode as the reaction occurs. The electrode here implies something that conducts charges, whether or not it is also the reductant does not change the fact that the 'reacting' part of the electrode gives electrons to the 'conducting' part of the electrode.

I would however like to hear your justification for another option(s). I probably haven't considered it fully.

in a number of practice exams i did, fuel cells were siad to be rechargable, however this was not often done in practice.... why would vcaa ask a question that requires students to know that electrons flow from one part of the electrode to another... dno, i dont think they'll accept two answers, but searching on th enet it also states that fuel cells can be recharged....

If fuell cells are rechargable doesn't that make A correct too? As the reactants and products would have to be kept in the cell?
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mirra250

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Re: MCQ 19
« Reply #13 on: November 11, 2010, 01:55:58 pm »
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I still think C is worded incorrectly and yes im trying to argue so it makes me feel better.

For eg:
In a reaction of Cu2+ ions and Fe (s)

Here we would say that Fe(s) is the reductant right? and also the anode?

yes this is what i think too, the reductant=anode..

Yes, that is correct. However, it will still (to some extent), flow from the 'surface' of the electrode to the 'center' of the electrode as the reaction occurs. The electrode here implies something that conducts charges, whether or not it is also the reductant does not change the fact that the 'reacting' part of the electrode gives electrons to the 'conducting' part of the electrode.

I would however like to hear your justification for another option(s). I probably haven't considered it fully.
That does not support answer C then. Answer C states that the "Electrons pass FROM the reductant TO the anode...". If the reductant is the anode (ie Fe (s) ) this cannot happen hence is not correct. All answers are wrong if you ask me. But, seeing as I did option D, im hoping that fuel cells can infact be recharged!

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Re: MCQ 19
« Reply #14 on: November 11, 2010, 01:57:11 pm »
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Since when was fuel cells rechargeable?
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