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May 05, 2024, 01:29:52 pm
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Author Topic: Quick Probability Question  (Read 356 times)  Share 

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El Carlos

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Quick Probability Question
« on: September 13, 2011, 06:05:37 pm »
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Here's something that stumped me while studying for my Prob Sac:

"For a given binomial distribution, p=1/3. The pr for obtaining a run length of 6 successes is":


How would I go about identifying the other values, and working this out?
I honestly thought this question was incomplete.
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paulsterio

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Re: Quick Probability Question
« Reply #1 on: September 14, 2011, 10:20:34 pm »
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Run length of 6 successes = Success,Success,Success,Success,Success,Success

So Pr(S,S,S,S,S,S) = Pr(S) ^ 6 (they're independent)
Which would equal (1/3)^6 so 1/729 :)
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