Is the answer, no solution ??
cause i find it easiest to just put these into a matrix..
1 4 3
2 1 -1
3 -1 -4
then find the determinant, which for this one = 0. so no solution.. ?
just becareful that if the determinant is 0 it does not necessarily mean no solutions, could mean infinite solutions as well
is there a way to proceed onwards from there to figure out which one it is using matrices ?
This is probabaly a really really easy question, just my brain's not working
Solve for x, x∈[-π ,π ]
sin x= -1/2
thanks in advance.
sin pi/6 = 1/2
so pi/6 is your base angle.
you need to figure out where sin is -1/2, in the given domain of [-pi,pi.]
since you're looking for -1/2, and sine is negative in the 3rd, 4th quadrants. so you'll have 2 solutions.
using the unit circle,
1) pi + (pi/6) = 7pi/6 , which is also the same - 5pi/6
2) 2pi - (pi/6) =11pi/6 , which is also the same as -pi/6