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April 28, 2024, 05:09:23 am

Author Topic: VCE General & Further Maths Question Thread!  (Read 759239 times)  Share 

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Yacoubb

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Re: VCE Further Maths Question Thread!
« Reply #135 on: July 20, 2013, 03:19:36 pm »
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Hi,
Just had a linear sac, and there was a m.c question which i wasn't quite sure about.

Mr Newcomer and Mrs latecomer leave the car park at the same time. If Mr newcomer arrives at the car park at 10:00 am, and Mrs latecomer is charged $24, what is the latest time Mrs latecomer can arrive at the car park?

There was graph in the question, although i can't upload a pic of it as the file is to big, so i will write it out.
- After 0 minutes up until 60 minutes the charge is $10.
- After 60 minutes up until 120 minutes the charge is $24.
- After 120 minutes the charge is $35.

a) 10:01 am
b) 10:59 am
c) 11:01 am
d) 11:59 am
e) the same time as Mr Newcomer

Both Mr Newcomer and Mrs Latecomer arrive at the same time. If Mr. Newcomer arrives at 10AM, and Mrs. Latecomer pays $24, that means she would have had to have been there between 1 and 2 hours (excluding 2 hours) after 10 (i.e. 11:59). Hence, the answer is D.

jimmy22

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Re: VCE Further Maths Question Thread!
« Reply #136 on: July 20, 2013, 05:49:55 pm »
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Both Mr Newcomer and Mrs Latecomer arrive at the same time. If Mr. Newcomer arrives at 10AM, and Mrs. Latecomer pays $24, that means she would have had to have been there between 1 and 2 hours (excluding 2 hours) after 10 (i.e. 11:59). Hence, the answer is D.

ok, but where did it say they arrived at the same time. It only said that they left at the same time.

BubbleWrapMan

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Re: VCE Further Maths Question Thread!
« Reply #137 on: July 20, 2013, 06:28:26 pm »
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The answer is "61 minutes before she leaves". There isn't enough info.
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Yacoubb

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Re: VCE Further Maths Question Thread!
« Reply #138 on: July 20, 2013, 06:49:32 pm »
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ok, but where did it say they arrived at the same time. It only said that they left at the same time.

Sorry I meant left - I misread that part of the question.

tomrox356

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Re: VCE Further Maths Question Thread!
« Reply #139 on: July 23, 2013, 10:18:32 pm »
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Does anybody know how i can get my hands on copious amounts of further exams? not the VCAA ones as i already have them but all the other ones from various companies?
for instance a link to download exams? or where can i find them???
Please help!
cheers :)

jeanweasley

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Re: VCE Further Maths Question Thread!
« Reply #140 on: July 23, 2013, 10:23:20 pm »
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Does anybody know how i can get my hands on copious amounts of further exams? not the VCAA ones as i already have them but all the other ones from various companies?
for instance a link to download exams? or where can i find them???
Please help!
cheers :)

I recommend going to itute.com Although some of the links appear to be broken, most of them are pretty accessible.
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jeanweasley

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Re: VCE Further Maths Question Thread!
« Reply #141 on: July 23, 2013, 10:32:32 pm »
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Hi guys

I need help with VCAA 2006 Exam 2 question (Mod 3) Question 3b.
Now I'm fine with normal inequalities but I have trouble understanding what it means when they use the words a is at least twice as b.

For example if y represents the number of dogs clipped and x the number of dogs washed, explain how would one get the inequality of y>/(greater than or equal to) 2x
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Yacoubb

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Re: VCE Further Maths Question Thread!
« Reply #142 on: July 23, 2013, 10:44:40 pm »
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Quote
Now I'm fine with normal inequalities but I have trouble understanding what it means when they use the words a is at least twice as b.


'At least' means that it must either be greater than or equal to.

So, if the number of dogs clipped is at least twice the number of dogs washed
x = number of dogs washed
y = number of dogs clipped

y is at least 2 x
y must be either equal to or greater than 2x

y>(greater than or equal to) 2x

jeanweasley

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Re: VCE Further Maths Question Thread!
« Reply #143 on: July 24, 2013, 09:42:17 am »
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'At least' means that it must either be greater than or equal to.

So, if the number of dogs clipped is at least twice the number of dogs washed
x = number of dogs washed
y = number of dogs clipped

y is at least 2 x
y must be either equal to or greater than 2x

y>(greater than or equal to) 2x
thanks for that. I get it now but I think I'll have to read the question four times before I really get the hang of it.
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Stick

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Re: VCE Further Maths Question Thread!
« Reply #144 on: July 24, 2013, 10:28:44 pm »
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These come with practice. Check your answer using a test point. :)
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vashappenin

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Re: VCE Further Maths Question Thread!
« Reply #145 on: July 27, 2013, 08:45:12 pm »
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Guys I hate chapter 14 from the Essentials textbook for geometry and trigonometry :@ :@ :@
I'm struggling with it so much! I'd probably have to say this the chapter that I've struggled with the most thus far in further, and it's really annoying me!
Here's the questions I need help with:
- Ex 14a: I don't understand bearings! :S q7, 16, 19
- Ex 14b: Is there a difference between due north (/S/W/E) and north (/S/W/E)?? q1d, 2f, 5, 6, 8, 9, 11, 12
- Ex 14c: How the hell do I work with contour maps?!?! q2

Sorry I know there's a lot but I've got a test coming up on monday or tuesday and I need to have these clarified or I'm basically screwed :S

Thanks!
« Last Edit: July 27, 2013, 09:32:07 pm by vashappenin »
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Re: VCE Further Maths Question Thread!
« Reply #146 on: August 05, 2013, 05:59:24 pm »
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i need help:

Question one:
equipment is brought for $13000. In 5 years time it will depreciate in value to $4000. Assuming it depreciates by the straight line method, it depreciates annually by how much?

Question two:
equipment is brought for $2250. If for every use it depreciates by 0.08 cents, how many uses will it take to depreciate it to a value of $1000?
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RKTR

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Re: VCE Further Maths Question Thread!
« Reply #147 on: August 05, 2013, 07:31:57 pm »
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i need help:

Question one:
equipment is brought for $13000. In 5 years time it will depreciate in value to $4000. Assuming it depreciates by the straight line method, it depreciates annually by how much?

Question two:
equipment is brought for $2250. If for every use it depreciates by 0.08 cents, how many uses will it take to depreciate it to a value of $1000?
total depreciation = 13000-4000=9000
annual=9000/5=1800

depreciation=2250-1000=1250
depreciation per use =0.08
number of uses =1250/0.08 =15625 uses
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lolipopper

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Re: VCE Further Maths Question Thread!
« Reply #148 on: August 05, 2013, 07:34:39 pm »
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total depreciation = 13000-4000=9000
annual=9000/5=1800

depreciation=2250-1000=1250
depreciation per use =0.08
number of uses =1250/0.08 =15625 uses

I got the same answer for question 1. but for question two i think by 0.08 cents, it means $0.0008. Just clarify this part.
Thank you friend.
2014: Monash University, Law

Yacoubb

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Re: VCE Further Maths Question Thread!
« Reply #149 on: August 05, 2013, 09:54:45 pm »
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In linear programming, when do we use points within the feasible region as opposed to the vertices of the feasible region? I mean, I was stumped when I looked at a question in Checkpoints like that, and especially because I've never come across it.

On the bright side, 1 SAC left for Further (well, practically 2, but my Graphs+Relations SAC will be finished early next week). Then its on to practice exams!