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April 28, 2024, 09:34:59 am

Author Topic: VCE General & Further Maths Question Thread!  (Read 759267 times)  Share 

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jeanweasley

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Re: VCE Further Maths Question Thread!
« Reply #165 on: August 15, 2013, 11:55:34 am »
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Just a question regarding constraints in linear graphing:

If the point is a decimal and the situation you're talking about involves whole numbers, do you round up or round down?

Eg. If the point is (21.6, 12.3)

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Re: VCE Further Maths Question Thread!
« Reply #166 on: August 15, 2013, 05:08:55 pm »
+1
It depends on what the variables actually are. In most practical cases, you'll be rounding down as the items are discrete. However, when simply dealing with numbers, you'll round to the nearest integer. Check the question too, since it may specify what to do. :)
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jimmy22

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Re: VCE Further Maths Question Thread!
« Reply #167 on: August 20, 2013, 06:37:09 pm »
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Hi,
If a 1 mark question stated, 'Give one reason why a dummy activity may be used in a network,"

Would, " A dummy activity may be used in a network to ensure that all predecessor activities are properly accounted for," be sufficient for the mark?

Thanks

BLACKCATT

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Re: VCE Further Maths Question Thread!
« Reply #168 on: August 25, 2013, 09:18:10 pm »
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Asking a question for a friend of mine :)

From a point, A, due north of a tower, the angle of elevation to the top of the tower is 45◦.
From a point, B, 100 m on a bearing of 120◦ from A, the angle of elevation is 26◦. Find the
height of the tower.

can someone help with this question?

aestheticatar

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Re: VCE Further Maths Question Thread!
« Reply #169 on: August 25, 2013, 10:31:14 pm »
+1
can someone help with this question?

I tried roughly sketching it out first. I've attached the bird's eye view and side views of the scenario to help.
If you follow my sketch:

Let height of tower = x metres
Let horizontal length from tower to B = y metres

As angle of elevation to top of tower from A is 45 degrees, we know horizontal distance from tower to A is also x metres (equal to height of tower).

As angle of elevation to top of tower from B is 26 degrees, we can use SOHCAHTOA to calculate that:
tan(26) = x/y
Transpose to find y in terms of x:
y = x/tan(26)

Use cosine rule on triangle (bird's eye view) to determine value of x:
y^2 = x^2 + 100^2 – 2(x)(100)cos(60)
(x/tan(26))^2 = x^2 + 100^2 – 2(x)(100)cos(60)

Solve for x using CAS:
x = 42.40, -73.61

x must be 42.4 metres as x > 0
Thus height of tower being x, is 42.4 metres tall.

Hope I helped! :)
P.S. Sorry for the dodgy drawing!


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Re: VCE Further Maths Question Thread!
« Reply #170 on: August 26, 2013, 03:56:38 pm »
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thanks! that helped a lot  :)

jeanweasley

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Re: VCE Further Maths Question Thread!
« Reply #171 on: September 01, 2013, 01:58:30 pm »
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Hi,

I need help with this question.

I have been given the matrix q and the matrix qrx and the question asks me to solve for x. How would I do this? I know that I have to use the inverse somewhere but if X and R are unsolved, how would I do this?

Here's the actual question.

Given Q  (2x2) no from left to right, first row then second is -2,4,3 and -2. and QRX is (2x1) top to bottom -24 and 32.
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Yacoubb

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Re: VCE Further Maths Question Thread!
« Reply #172 on: September 01, 2013, 09:31:24 pm »
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Hi,

I need help with this question.

I have been given the matrix q and the matrix qrx and the question asks me to solve for x. How would I do this? I know that I have to use the inverse somewhere but if X and R are unsolved, how would I do this?

Here's the actual question.

Given Q  (2x2) no from left to right, first row then second is -2,4,3 and -2. and QRX is (2x1) top to bottom -24 and 32.

What answer did you get?

I did a method but I don't know if my answer is right

lolipopper

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Re: VCE Further Maths Question Thread!
« Reply #173 on: September 01, 2013, 10:36:04 pm »
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Hi,

I need help with this question.

I have been given the matrix q and the matrix qrx and the question asks me to solve for x. How would I do this? I know that I have to use the inverse somewhere but if X and R are unsolved, how would I do this?

Here's the actual question.

Given Q  (2x2) no from left to right, first row then second is -2,4,3 and -2. and QRX is (2x1) top to bottom -24 and 32.

i dont get what you are asking. is this question in the vcaa exams or essentials further book?
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Insa

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Re: VCE Further Maths Question Thread!
« Reply #174 on: September 17, 2013, 12:32:25 am »
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Hey guys :D Could anyone please help me with question in relation to networks? Thank you.
« Last Edit: September 17, 2013, 12:34:19 am by Insa »
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RKTR

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Re: VCE Further Maths Question Thread!
« Reply #175 on: September 17, 2013, 05:13:20 pm »
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E won a match. the opponent who lost to E also only won a match. therefore E must have defeated A.
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Re: VCE Further Maths Question Thread!
« Reply #176 on: September 18, 2013, 01:15:06 pm »
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Do we need to connect the dots on a time series if we plot one? Or can we leave them disconnected?
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Re: VCE Further Maths Question Thread!
« Reply #177 on: September 18, 2013, 09:17:26 pm »
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Connect them together.
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Yacoubb

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Re: VCE Further Maths Question Thread!
« Reply #178 on: September 19, 2013, 07:49:30 pm »
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Would the following explanations be appropriate (they're for linear regression): i've just used example figures.

Coefficient of determination
87.56% of the variation in arm span can be explained by variation in height.

Describing a relationship:
From the scatterplot, it can be seen that there is a strong, negative linear relationship between number of errors on a test and the period of time spent studying, with no outliers.

Gradient:
On average, the final weight of Jane decreases by 1.44kg for every additional day spent working out.

Y-intercept:
On average, Jane's final weight at the start of the weight-loss program, is 96kg.

^ Are these templates for such questions okay? Thanks!

jimmy22

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Re: VCE Further Maths Question Thread!
« Reply #179 on: September 19, 2013, 07:59:14 pm »
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They look good to me.

The only thing that i might've added is for the Coefficient of determination you could also say in the next sentence, "12.46% of the variation in arm span can be explained by other factors such as ......."

Not sure if it's necessary though.