does anyone know how to solve this using simultaneous equations?
Linda thinks of a two-digit number. The sum of the digits is 8. If she reverses the digits, the new number is 36 greater than her original number. What was Linda’s original number?
i know that the answer will be 26 but i can't figure out how to find this answer using simultaneous equations
thanks in advance!
Lets assume that our 2 digit number will be in the form of \(AB\)
So we know the sum of the digits is 8, so \(A+B=8\), and we also know the value of this particular 2 digit number will be \(10A+B\) where \(A\) is tens digit and \(B\) is units digit.
When we reverse these digits the value of that number will be \(10B+A\), as we have switched the positions of the tens and units digit.
To determine the difference expression of the original and reverse we will simply do \(\left(10A+B\right)-\left(10B+A\right)\Rightarrow 9A-9B\)
So in this question we have formed two simultaneous equations, that is...
\(A+B=8\), and \(9A-9B=36\)
Hope this helps, if you have trouble solving these simultaneous equations don't hesitate to ask for help!
EDIT: Beaten by Sine by literally seconds lmao