its 48k. its the same tyres for all 4 wheels but tyres in front wear out faster.
i remember seeing this problem ages ago. the way i did it back then was to assign each tyre 1 'hitpoint'. each kilometre travelled would reduce the 'hit points' of the front tyre by 1/40k and the rear tyre by 1/60k.
obviously if you switch the front and back tyres after x kilometers travelled, you will get more than 40k.
so the question is to find the x at which you should switch your tyres, such that they will reach 0 hit points at the same time. which happens to be the harmonic mean of 40k and 60k, which you will see if you do all the algebra.
btw, is this a 11-20 problem or 21-30 problem?
i want to do it =(
Why aren't you doing it?
not in hs anymore