Hey guys!
I was wondering how the equation w=qv was derived for work done in an electric field? Thanks
Hey Professor Max Planck!
I thought you are the professor in this area, not sure why you would be asking us for help but I guess you are too great to remember minute details such as this. After all I'm sure you are busier with your investigation into the blackbody radiation and E=hf. But it is certainly my honour to help a person like you who have receive nobel prizes for your significant contribution to our physics world.
(Dont worry, I know you are not Max Planck hehehehe)
Ok so the simpler version of this derivation is simply substituting into the formula for
work, where the
force is the electric force experienced by a charged particle in an electric field and
displacement is distance the charged particle has moved as a result of this electric force.
Work done = Force x DisplacementWork = qE x dWork = qVThe more complicated version is actually more intuitive for me, so if you think you can follow my logic here, you can have a read. I feel like for me this is a better way of truly understanding how W=qV really came about.
Recall that
1 Voltage = 1 Joule of energy available to move 1 Coulomb of charge. When voltage is applied to a pair of parallel plates, an electric field is produced
( E = V/d ). Now, in this electric field, a charged particle will experience a force
( F = qE ). This force will cause the charged particle to accelerate
( F = ma ) and hence the velocity of this charged particle will increase. Because the velocity increases, the charged particle's kinetic energy also increase
( KE = 1/2 mv2 ). Since kinetic energy is a form of work done on an object, it has the unit Joules. If we now compare the unit for voltage, which is Joules/Coulomb with the unit for kinetic energy (work), which is Joules, then we can see that all we need to do to convert for voltage to work is to multiply voltage by q (i.e. J/C x C = J). Hence formula for work is W = qV.
Best Regards
Happy Physics Land