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April 27, 2024, 09:14:29 pm
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Author Topic: Binomial Distribution  (Read 1141 times)  Share 

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sondang

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Binomial Distribution
« on: June 11, 2012, 10:13:35 pm »
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I've been stuck on this exercise and I can't seem to apply the worded problems to the formula. Maybe it's because I don't understand the formula itself.

Here's a question from the text book:

If the probability of a female child being born is 0.48, find the probability that a family with exactly three children has at least one child of each sex.

Help is greatly appreciated :) Thanks!

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fred42

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Re: Binomial Distribution
« Reply #1 on: June 11, 2012, 10:55:12 pm »
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At least one of each means 2 boys and one girl or 2 girls and one boy.

Pr(GGB) = 3C2 X 0.48^2 X 0.52 = 0.359424
Pr(GBB) = 3C1 X 0.48 X 0.52^2 = 0.389376

Prob required is the sum = 0.7488
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