Quick Question on Parametrics:
Find the equation of the tangent to the parabola x=4t, y=2t^2 at the point where t=3.
Thank you
You can do this a whole bunch of ways. I think it's easiest to find the parabola first, differentiate, and find the tangent the usual way etc.
Then, we can find the tangent the normal way! First, you will need to x and y coordinates at t=3. We can sub this t value straight into the equations we are given to find them.
I'll leave you to find the tangent from there: just use normal calculus!
You can also use the chain rule method (ie find the first derivative of x with respect to t, y with respect to t, multiply them etc.). That may or may not be quicker, just depends on how you visualise the maths.
Jake