Yo can someone help me with 11.11 and 11.13 e
11.11 I thought pressure was inversely proportional to volume and therefore I don't understand why the pressure increases. I get 0.514 metres cubed by doing PxV is a constant
11.13 How are you meant to answer this question when all three of pressure volume and temperature change
EDIT: Whoops I just realised all you do is PV=nRT for 11.13
You're right, pressure is inversely proportional to volume but you have to keep the other variables (temp and number of moles) constant. So as the pressure inside the tyre increases, the air that started off in the tyre decreases in volume (gets squeezed into a smaller space by the new air).
For the air inside the tyre, we want to find the new volume it occupies (to then find how much volume the new air takes up). Since it's the same air, the number of moles is constant so we can use PV=constant
P
1V
1=P
2V
2V
2=P
1V
1/P
2=105*0.150/360
=0.04375 m
3 Note that since it's P1/P2 you can use whichever units you choose for pressure but they must be the same.
Volume of new air inside the tyre (at pressure of 360kPa) is the remaining volume = 0.150 - 0.04375 = 0.10625 m
3Volume at atm pressure: use the same equation as number of moles & temp stays the same
V
1=P
2V
2/P
1=360*0.10625/105
=0.364 m
3Also note that you need to take into account sig figs if applicable