Hello,
I am stuck on all of the multiple choice questions and Q 2.1 b) in the link below. Can anyone please help me out? Thanks
Sure thing David!
- 1.1 is (D), because all the others have nonsense words with nothing to do with anything
- 1.2 you are right with (D)
- 1.3 is (B), the energy of an emitted photoelectron is \(E=hf-\phi\). It has nothing to do with intensity, only the frequency of light and the work function of the metal.
- 1.3 is C), because that's just how it was
As for the last one, remember that the energy of emitted photoelectrons is always \(E=hf-\phi\). Again, intensity has nothing to do with that - Intensity only releases MORE photoelectrons, it doesn't change their individual energies. Therefore, if the light doesn't have a high enough frequency, you won't get a photocurrent no matter how intense your light is