Your mol values look good
So we first have the sodium carbonate
n(Na2CO3 ) = 0.5 M x 0.025 = 0.0125 mol
and from the chemical equation we find that
n(HCl) = 2 x n(Na2CO3) = 2 x 0.125 = 0.250 mol
Now if we want to find the concentration of something we will rearrange the equation n = cv into c = n/v
and the current information that we have are the "moles" of HCl which is 0.250 mol and volume used for the titration 23.92 mL
Let us know if you need further assistance
Still a little confused ahaha
- So I've also figured out concentration of HCl in the titre by doing c = 0.250/0.02392 which is 10.451M
- Then I tried to use the values of the cleaner before and after the dilution to find the original concentration of HCl in the concrete cleaner by using C
1V
1 = C
2V
2 formula and substituting V
1 for 25.00 (the original undiluted volume of the cleaner), C
2 for 10.451 (the concentration of the HCl in the titre I found above) and V
2 for 250.0 (the diluted volume of the cleaner).
- After solving this equation, I got 104.51M which is way off the correct answer.
Where have I gone wrong?