Some questions

[3Xamz]

Woah, really? I thought they all spread out equally until they reach a point of diffraction.

Then how can we apply;

I = P/(4pir^2)

It's the same intensity equation and its independent of frequency...

This formula assumes that it spreads out in a spherical shape but this is not the case for most speakers as there sound is stronger in front of the speaker especially for higher frequency's

Yeah true but my argument is that the intensity of the equation is independent of the frequency. I'm still having trouble getting my head around how one frequency can be more intense at one point than another?

[kyzoo]

It's probably because of diffraction; the more a wave diffracts (larger wavelength and smaller frequency), then the more intense that wave will be at points which the sound wave needs to diffract to reach.

[Chavi]

It's probably because of diffraction; the more a wave diffracts (larger wavelength and smaller frequency), then the more intense that wave will be at points which the sound wave needs to diffract to reach.

But no diffraction occurs in air. . .?

[kyzoo]

then i dunno then =X

[3Xamz]

Urgh, this is frustratingly confusing T___T

[taiga]

On wave-particle duality:

When does it occur, and when does it exist?

I can't wrap my head around the concept of standing waves, and how quantised energy levels of the atom relate to it :X

[Chavi]

On wave-particle duality:

When does it occur, and when does it exist?

I can't wrap my head around the concept of standing waves, and how quantised energy levels of the atom relate to it :X

When electrons spin around a nucleus then spin in waves - standing waves to be precise. These standing waves only occur if the circumference of the orbit is a multiple of the electrons DeBroglie wavelength - hence the quantization of energy levels.
Basically in a nutshell, you have to know that electrons are particle that act like waves, and light is a wave that exhibits particle like behaviour.