over9000 questions thread

[TrueTears]

The closest way from P to B is in a straight line (hence perpendicular) so

but

Since P lines on , then where q is a real constant.

so

expanding all that yields

solving for q yields

subbing this back in = = i+j

[Over9000]

Thanks, would never have thought of that 

[Over9000]

Continuation of that question, Find the position vector of D, the centre of the circle through A,B and P.

[TrueTears]

http://vcenotes.com/forum/index.php/topic,9192.270.html

[Over9000]

k, so I got 2i + 2j + 2k, is that right

[TrueTears]

no i got 2i + 3j + 3k

[Over9000]

How did you get that?

[TrueTears]

let D be the mid point of

[Over9000]

Oh, ok, I get it
I did , thats why it was wrong

[Over9000]

for the graph , what are the coordinates of its stationary point

[TrueTears]

There are no stationary points.

[Over9000]

Lol, I mean point of symmetry, P

[TrueTears]

We can see that the graph has been transformed, (there has been dilations from the y axis and translations in the x axis.)

so we must find the new endpoints of the domain of the transformed graph

the domain of is [-1,1]

so for the transformed graph it will be

solve that and you get

mid point of that is 6. so sub 6 in the equation yields

so P(6,5)

[Over9000]

Thanks

[Over9000]

What is the inverse of