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May 13, 2024, 05:47:48 pm

Author Topic: Dekoyl's Questions  (Read 21804 times)  Share 

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Over9000

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Re: Dekoyl's Questions
« Reply #15 on: March 29, 2009, 02:50:09 am »
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btw, wats the answer to the second question, I have 7.3m, not sure if its right?? (ill post my working if it is)
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dekoyl

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Re: Dekoyl's Questions
« Reply #16 on: March 29, 2009, 02:51:47 am »
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btw, wats the answer to the second question, I have 7.3m, not sure if its right?? (ill post my working if it is)
The answer is 2.87m.

Over9000

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Re: Dekoyl's Questions
« Reply #17 on: March 29, 2009, 02:52:46 am »
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oh, kk, way off, ill have to check where I made an error  ;D
Gundam 00 is SOOOOOOOOHHHHHHHHH GOOOOOOOOOOODDDDDDDDDDDD I cleaned my room

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Over9000

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Re: Dekoyl's Questions
« Reply #18 on: March 29, 2009, 03:08:49 am »
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Ok, I shall try to explain what the picture is like
Inclined plane to horizontal, Imagine a block halfway (doesnt have to be) along the incline plane and a pulley (simple one pulley) at the very top of the plane, now, the rope connects to the block which is on the inclined plane goes over the single pulley and then downwards connected to another lighter block. So you can imagine a block on an inclined plane, connected to a block which is hanging freely in mid air via the pulley system (I dont know if you will understand this, a bit hard to explain).

So (block on inclined plane) = (block hanging freely)
     
     
     
     
     
     
     
     use constant acceleration forumla
     
     

If you still cant picture it (which may make the working out seem hard to comprehend), send me a pm and ill scan my working out of the question by hand.
« Last Edit: March 29, 2009, 03:13:52 am by Over9000 »
Gundam 00 is SOOOOOOOOHHHHHHHHH GOOOOOOOOOOODDDDDDDDDDDD I cleaned my room

VCE 200n(where n is an element of y): Banter 3/4, Swagger 3/4, Fresh 3/4, Fly 3/4

dekoyl

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Re: Dekoyl's Questions
« Reply #19 on: March 29, 2009, 03:18:04 am »
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No it's okay ;D Your explanation was great so I got it.
Thanks heaps again Over9000 =]

dekoyl

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Re: Dekoyl's Questions
« Reply #20 on: March 29, 2009, 03:23:03 pm »
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Momentum: A heavy truck collides head on with a car one fifth its mass. The car and truck were both travelling at 20 above the speed limit. During the collision, what is the ratio? Answer: 1


Thanks!

dcc

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Re: Dekoyl's Questions
« Reply #21 on: March 29, 2009, 03:41:46 pm »
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Momentum: A heavy truck collides head on with a car one fifth its mass. The car and truck were both travelling at 20 above the speed limit. During the collision, what is the ratio? Answer: 1

What is the ratio?  Which ratio?

dekoyl

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Re: Dekoyl's Questions
« Reply #22 on: March 29, 2009, 03:44:38 pm »
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What is the ratio?  Which ratio?
That's the exact question. =(
It's meant to be in relation to momentum and impulse. And the exact answer is 1. (Ratio of 1:1?)

TrueTears

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Re: Dekoyl's Questions
« Reply #23 on: March 29, 2009, 03:49:56 pm »
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Momentum: A heavy truck collides head on with a car one fifth its mass. The car and truck were both travelling at 20 above the speed limit. During the collision, what is the ratio? Answer: 1

What is the ratio?  Which ratio?
yeah, what ratio does it ask? ratio of the speed? or...?
PhD @ MIT (Economics).

Interested in asset pricing, econometrics, and social choice theory.

dekoyl

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Re: Dekoyl's Questions
« Reply #24 on: March 29, 2009, 03:56:23 pm »
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yeah, what ratio does it ask? ratio of the speed? or...?
This is from page 11 of "Motion question booklet.doc" in the thread you created with motion notes + practice SACs.
I'm not sure; This is the exact question (copy + paste):
Quote
20. A heavy truck collides head on with a car one fifth of its mass. The car and the truck were both travelling at 20 kmh-1 above the speed limit.
During the collision what is the ratio     ?

Ans: 20) 1

Yeah looks like there might be something missing judging from the space between 'ratio' and '?'.

Thanks anyway dcc and TT

TrueTears

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Re: Dekoyl's Questions
« Reply #25 on: March 29, 2009, 04:08:25 pm »
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hmm yeah, might be a faulty question lol
PhD @ MIT (Economics).

Interested in asset pricing, econometrics, and social choice theory.

dekoyl

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Re: Dekoyl's Questions
« Reply #26 on: March 29, 2009, 09:30:26 pm »
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A simple one:

A rubber ball bounces from a height of 1.0m onto a wooden table and rebounds to a height 0.8m.
Explain how the momentum is conserved during the collision between the ball and the table.
Worth 2 marks and I didn't get any marks. :(

TrueTears

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Re: Dekoyl's Questions
« Reply #27 on: March 29, 2009, 09:36:07 pm »
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Momentum is always conserved, here the ball does not rebound to its original height because some momentum is transferred into the table.

Considered the table as a car and the ball as a much lighter car.

The table car is stationary, where as the ball car crashes head on into the table car.

Assuming they both rebound, the table car rebounds a tiny bit (most likely none here cos the ball is so light) and the ball car bounces back in the direction where it came from, but it's lost some speed (because its transferred some momentum into the table car) and so it does not go back fully where it started.
PhD @ MIT (Economics).

Interested in asset pricing, econometrics, and social choice theory.

dekoyl

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Re: Dekoyl's Questions
« Reply #28 on: March 29, 2009, 09:38:42 pm »
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Thanks TT - I guess my explanation wasn't good enough :P But your explanation should please my marker.

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Re: Dekoyl's Questions
« Reply #29 on: March 29, 2009, 09:41:01 pm »
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Momentum is always conserved, here the ball does not rebound to its original height because some momentum is transferred into the table.

Considered the table as a car and the ball as a much lighter car.

The table car is stationary, where as the ball car crashes head on into the table car.

Assuming they both rebound, the table car rebounds a tiny bit (most likely none here cos the ball is so light) and the ball car bounces back in the direction where it came from, but it's lost some speed (because its transferred some momentum into the table car) and so it does not go back fully where it started.

And the Normal Reaction Force> Weight, otherwise it wouldn't bounce.
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