Hi guys,
Say you are doing a volumetric analysis with the unknown solution being in the conical flask and the chemical with the known concentration is in the burette. What happens if the conical flask is rinsed by accident with the unknown solution?
Because you have more mol in the conical flask than expected, you'd need more titre from the burette, so you'd calculate a higher mol and hence higher concentration than expected. Is this right?
But what happens if you switch this around, and the known is in the conical and the unknown is in the burette, but you still wash the conical flask with the unknown? Because you have some of the unknown in the conical flask, it would already react with the known which would mean you would need less titre from the burette, which would mean that you would calculate a higher concentration right?
Is this reasoning right? Thanks