Hey! I'm not sure if this is where I am supposed to post this, as it is my first post - so please let me know if I'm doing anything wrong.
I'm doing some holiday HW for 1/2 Methods and have come across a question I can't do, and I can't find any useful resources elsewhere. This is the question:
ABCD is a quadrilateral with angle ABC a right angle. D lies on the perpendicular bisector of AB. The coordinates of A and B and (7,2) ad (2,5) respectively. The equation of line AD is y = 4x-26.
a) Find the equation of the perpendicular bisector of the line segment AB.
b) Find the coordinates of point D.
c) Find the gradient of the line BC.
d) Find the value of the second coordinate, c, of point C(8,c).
e) Find the area of quadrilateral ABCD.
So far, my answers are:
a) y=5/3x-4
b) (66/7,82/7)
c) 5/3
d) C(8,15)
But part e has me stumped! How can I work out the area when I only know the vertices, and it is an irregular shape?
I was thinking of finding the area of triangle ABC (a right angled triangle) and then using perpendicular lines and simultaneous equations to find the height of ACD to find the area of that triangle, but I'm not sure if that would work or if there is an easier way.
Thanks in advance!