kingpomba's noobtacular question-a-rama thread

[Stroodle]

For your second question your book is wrong.

[Stroodle]

For your 3rd question:

[the.watchman]

The image of 3 is

The pre-image of 11 is when ,

For the third part of this question, it is asking when

So ,

[Stroodle]

For the last questions I can't quite remember the definitions of "image" and "pre-image", but I think that the image of 3 is:





and I think the pre-image is where :





For the last part of that question:

[the.watchman]

For the last questions I can't quite remember the definitions of "image" and "pre-image"

The image of a number is the 'y-value' or the value the function takes with that number (eg. )

The pre-image of a number is the 'x-value' or the value of the variable when the function equals that number (eg. )

I hope this clears things up!

[Stroodle]

For the last questions I can't quite remember the definitions of "image" and "pre-image"

The image of a number is the 'y-value' or the value the function takes with that number (eg. )


The pre-image of a number is the 'x-value' or the value of the variable when the function equals that number (eg. )

I hope this clears things up!

Awesome. Thanks.

[slothpomba]

For your 3rd question:

Whered the 6x and 12x come from

[the.watchman]

For your 3rd question:

Whered the 6x and 12x come from

It's from the expansion of

For confirmation, use the formula

[slothpomba]

shouldnt it be 24x or am i mistaken
wait i see

[the.watchman]

shouldnt it be 24x or am i mistaken

No, from the expansion of the first cube, we get BUT there is another from the term. I hope this makes sense

[slothpomba]

oh edited too late thanks anyway

[slothpomba]

I was thinking something like this






 

didn't work though

This did:















My question is...whats wrong with my first one.. how do i decide to take the 3x away instead of dividing everything by 3 first, also in the last equation i moved 7 to the other side but it wouldnt happen if i chose to move 2 to the other side. How do i chose which no to move?

[TrueTears]

I was thinking something like this






 

didn't work though

This did:















My question is...whats wrong with my first one.. how do i decide to take the 3x away instead of dividing everything by 3 first, also in the last equation i moved 7 to the other side but it wouldnt happen if i chose to move 2 to the other side. How do i chose which no to move?

2x = x-3

x = -3

[Stroodle]

 

You can do it either way, you just made an error:

[slothpomba]

Same with
h(x) = 3x - 2

Find: x:h(x) = 0

maybe its cause i got 2 hours sleep last night i dont run well on lack of sleep