I honestly still have no idea..
If anyone could take the time to make a worked solution for me, I would really appreciate it. I'm not lazy, I just do not understand anything you are saying etc "second per second". I'm new to Physics and I feel like I'm going to fail it at this pace. I hope if anyone has used Jacaranda 1/2 Physics, can they please tell me whether it could be so complicated? If it is, I'm definitely dropping it =[
You calculates the acceleration to be 4 m/s^2. Aside from getting the units wrong your working here was fine.
This means that each second, the velocity changes by 4 metres per second (i.e. change of 4 metres per second per second)
In part a we start off at 100 m/s east. This is the same direction as our acceleration. After 1 second, the new velocity will be 104 m/s east. After another second, it will be 108 m/s east. After the 3rd second, it will be 112 m/s east... until eventually after 6 seconds it will be 100 m/s +(4m/s^2)(6s) = 124 m/s
In part be we start off at 100 m/s west. This is the opposite direction to our acceleration. After 1 second the velocity will be 96 m/s. After another second it will be 92 m/s. After 3 seconds it will be 88 m/s.... after 6 seconds it will be 100 m/s - (4 m/s^2)(6) = 76 m/s west
In both cases, we can use the forumla v = u + at to arrive at our answers. In this approach, we can jump straight to
a)
v = u + at
= 100 + (4)(6)
= 124
v= 124 m/s east
b)
v = u + at
= -100 + (4)(6)
= -76
v = 76 m/s west
I hope this clarifies things a bit