Author Topic: Physics Question (Read 632 times) Tweet Share

bloop · « **on:** July 16, 2017, 03:11:18 pm »

Hi I have a question and it is attached. The answer is C and I was wondering how you would get it.

kiwiberry · « **Reply #1 on:** July 16, 2017, 03:27:14 pm »

Quote from: bloop on July 16, 2017, 03:11:18 pm

Hi I have a question and it is attached. The answer is C and I was wondering how you would get it.

Hello, welcome to the forums!

Given the voltage and the distance between the electric plates, we can calculate the strength of the electric field:
$E =\frac{V}{d} = \frac{2.01}{0.005} = 402$ And then using the charge of an electron, we can calculate the electric force
$F=qE=1.602\times 10^{-19} \times 402= 6.44 \times 10^{-17} \text{ N}$

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Author Topic: Physics Question (Read 632 times) Tweet Share

bloop

Physics Question

kiwiberry

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