Yeah, they're never gonna assess this stuff (they did in one of my school's SACs but they did teach us it in class), it's just good to know if you're interested
It's a bit too much I think.
YOU DO NO NEED TO KNOW THE FOLLOWING, IT'S THERE FOR INTEREST ONLYFor those who are interested though:
Electrons from NADH molecules and stripped off by complex I. Naturally, the biproduct of this reaction is H
+. These electrons make their way through the complex itself, until they reach the docking site of coenzyme Q. The electrons reaction with coenzyme Q, making QH
2 (ubiquinol). In addition to this, complex I also pumps 4 protons (per NADH) from the matrix of the mitochondria to the intermembrane space. This pumping establishes a concentration gradient across the membrane, which also creates a charge difference across the membrane as well.
Electrons from FADH
2 molecules are stripped off by complex II. Similarly, they make their way through the metal centres in complex II until they reach the Q docking site. They react with Q and protons to make QH
2. Unlike complex I, complex II does not pump protons.
The QH
2 molecules synthesised at complexes I and II dock at complex III, where they are oxidised back to coenzyme Q. Thus, complex II has accepted the electrons from complexes I and II. These electrons pass along the complex, much in the same manner as complex I and II (through metal centres) and make their way to a cytochrome c docking site. Like coenzyme Q, cytochrome c can carry electrons. This is because it contains a haeme group in the centre, with the central ion being reduced from Fe
3+ to Fe
2+. The movement of the electrons through complex III drives the pumping of 4 protons for each FADH
2 or NADH molecule. Cytochrome c leaves complex III and sets off for complex IV.
Cytochrome c docks at complex IV, where it the haeme group is oxidised and the electrons donated to the complex. The electrons make their way through the complex's metal centres, driving the pumping of 2 protons per NADH/FADH
2 molecule. Once they have reached the "end" of the complex, they are combined with protons and molecular oxygen to form water, one of the biproducts of respiration (hooray!). This is the only step at which oxygen is required in all of aerobic respiration.
The proton gradient that has been established by the pumping of protons by complexes I, III and IV is used to fuel a process called chemiosmosis. The protons are allowed to diffuse back through the F
0 subunit of an enzyme called ATPase. This diffusion results in the rotation of the γ-subunit, which in a sense, bashes inorganic phosphate and ADP together synthesising ATP.
And that is the story of the ETC. Note as well that NADH produces more ATP than FADH
2. Remember that NADH enters at complex I, which pumps 4 protons. Thus, NADH electrons go through complexes I, III and IV (pumping 4, 4 and 2 protons respectively). FADH
2 electrons, however, bypass complex I and pass through complexes II, III and IV (pumping 0, 4 and 2 protons respectively). Given that NADH results in the pumping of 10 protons and FADH
2 the pumping of 6, it stands to reason that FADH
2 yields 40% less ATP molecules than NADH.