ATAR Notes: Forum
VCE Stuff => VCE Science => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Chemistry => Topic started by: ttn on September 13, 2010, 11:43:52 pm
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Hi, can you please help me out with this question.
50 ml of a solution of pH 2 is added to 450ml of water. What is the new pH?
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Use

= 10^(-2),
= 0.05,
=0.5
Calculate final concentration and use log to find the ph
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oh wow, thanks.
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Well initially it is 50 ml, and after being added to 450 ml it becomes 500 ml. Hence H+ has been diluted by a factor of 10. Every pH step is a dilution by a factor of 10. Hence the pH ought to just be 3 :)
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Just occured to me thats a good way of calculating the ph if you know both volumes :)
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Hence H+ has been diluted by a factor of 10. Every pH step is a dilution by a factor of 10. Hence the pH ought to just be 3 :)
Wow, didn't see pH like that, makes sense. Thanks. But don't you mean H3O+?
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Hence H+ has been diluted by a factor of 10. Every pH step is a dilution by a factor of 10. Hence the pH ought to just be 3 :)
Wow, didn't see pH like that, makes sense. Thanks. But don't you mean H3O+?
H+ and H3O+ are essentially the same thing, are they not? :O
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Hence H+ has been diluted by a factor of 10. Every pH step is a dilution by a factor of 10. Hence the pH ought to just be 3 :)
Wow, didn't see pH like that, makes sense. Thanks. But don't you mean H3O+?
H+ and H3O+ are essentially the same thing, are they not? :O
yeah pretty much