quick pH question

[ttn]

Hi, can you please help me out with this question.

50 ml of a solution of pH 2 is added to 450ml of water. What is the new pH?

[sajib_mostofa]

Use
= 10^(-2), = 0.05, =0.5

Calculate final concentration and use log to find the ph

[ttn]

oh wow, thanks.

[taiga]

Well initially it is 50 ml, and after being added to 450 ml it becomes 500 ml. Hence H+ has been diluted by a factor of 10. Every pH step is a dilution by a factor of 10. Hence the pH ought to just be 3

[sajib_mostofa]

Just occured to me thats a good way of calculating the ph if you know both volumes 

[ttn]

Hence H+ has been diluted by a factor of 10. Every pH step is a dilution by a factor of 10. Hence the pH ought to just be 3

Wow, didn't see pH like that, makes sense. Thanks. But don't you mean H3O+?

[Andiio]

Hence H+ has been diluted by a factor of 10. Every pH step is a dilution by a factor of 10. Hence the pH ought to just be 3

Wow, didn't see pH like that, makes sense. Thanks. But don't you mean H3O+?

H+ and H3O+ are essentially the same thing, are they not? :O

[Mao]

Hence H+ has been diluted by a factor of 10. Every pH step is a dilution by a factor of 10. Hence the pH ought to just be 3

Wow, didn't see pH like that, makes sense. Thanks. But don't you mean H3O+?

H+ and H3O+ are essentially the same thing, are they not? :O

yeah pretty much