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April 20, 2026, 02:26:27 am

Author Topic: Fibonacci Sequences  (Read 1028 times)  Share 

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Yendall

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Fibonacci Sequences
« on: May 25, 2012, 06:31:47 pm »
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Hello everyone!
I am little puzzled by this problem that I overcame in the textbook.
I understand Fibonacci Sequences and can solves problems like this for example:

Name the terms represented by:
i) t27 + t28

Obviously this would equal t29.
Those types of problems I understand.

However, this one stumped me, and i'm sure there is a simple way of solving it, the textbook just never explained it.

It is:
t11 + 2xt12 + t13

How do I deal with the 2xt12?

Thanks for any help you guys can provide!

Max.

EDIT: nevermind I understand this now:

t11 = 89
2xt12 = 288
t13 = 233

89 + 288 + 233 = 610
t15= 610
thus
t11+2t12+t13 = t15
« Last Edit: May 25, 2012, 09:05:13 pm by Yendall »
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plato

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Re: Fibonacci Sequences
« Reply #1 on: May 27, 2012, 04:23:25 pm »
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A more general method is
    t11 + 2xt12 + t13
=  (t11 + t12) + (t12 + t13)
=  t13  +  t14
=  t15

Yendall

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Re: Fibonacci Sequences
« Reply #2 on: May 27, 2012, 05:55:46 pm »
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A more general method is
    t11 + 2xt12 + t13
=  (t11 + t12) + (t12 + t13)
=  t13  +  t14
=  t15
oh i see how it would work like that, thank you! that would save much more time.
2013 - 2016: Bachelor of Computer Science @ RMIT
2017 - 2018: Master of Data Science @ RMIT
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VCE '12: | English | I.T: Applications | I.T: Software Development | Music Performance Solo |  Further Mathematics | Studio Arts |