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September 12, 2025, 02:04:31 am

Author Topic: Help with Faraday's Laws Question  (Read 645 times)  Share 

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emiinaaa

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Help with Faraday's Laws Question
« on: October 14, 2012, 10:29:00 pm »
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When 289,500 Coulombs of electricity are passed through an electrolytic cell containing molten potassium chloride, what are the masses of potassium and chlorine produced?

Mr(K)=39 and Mr(Cl2)=71

TheRajinator

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Re: Help with Faraday's Laws Question
« Reply #1 on: October 15, 2012, 04:27:32 pm »
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Q(C)=n(e)*96500
n(e)=289500/96500=3mol
n(K)=n(e)=3
therefore m(K)=Mr(K)*n(K)=39*3=117g
n(e)/2=n(Cl2)=1.5
m(Cl2)=Mr(Cl2)*n(Cl2)=71*1.5=106.5g
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emiinaaa

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Re: Help with Faraday's Laws Question
« Reply #2 on: October 15, 2012, 07:12:40 pm »
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charmanderp

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Re: Help with Faraday's Laws Question
« Reply #3 on: October 15, 2012, 07:21:19 pm »
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n(K)=n(e)=3

n(e)/2=n(Cl2)=1.5

Sorry I don't understand how you came to this..
Look in the electrochemical series and you'll find the mole ratio between electrons and potassium and electrons and chlorine.
University of Melbourne - Bachelor of Arts majoring in English, Economics and International Studies (2013 onwards)