General Solutions

[Homer]

has one more solutions for x?

[Jenny_2108]

Oh yes it is another solution..Wow this question is just terrible haha, probably really simple as well, I just don't get it.. T_T

and...another question...

Find the values of k, where k is a positive real number, for whic the equation 3 - ke^x - e^-x = 0 has one more solutions for x

3 - ke^x - e^-x = 0
=> 3e^x-ke^(2x) -1=0
Let e^x=a
Solve 3a-ka^2-1=0 by using quadratic formula

Do you mean one or more solution or more than one solution?
If one or more sol, let delta>=0, if more than one solution, delta>0

[destain]

Oh yes it is another solution..Wow this question is just terrible haha, probably really simple as well, I just don't get it.. T_T

and...another question...

Find the values of k, where k is a positive real number, for whic the equation 3 - ke^x - e^-x = 0 has one more solutions for x

3 - ke^x - e^-x = 0
=> 3e^x-ke^(2x) -1=0
Let e^x=a
Solve 3a-ka^2-1=0 by using quadratic formula

Do you mean one or more solution or more than one solution?
If one or more sol, let delta>=0, if more than one solution, delta>0

Sorry, I meant one or more, so do you have to solve using the quadractic formula? Or do you just use the discriminant thing? And also in this case would it be...a = 3 b= -k c= -1
or do you leave out the signs

[Jenny_2108]

Oh yes it is another solution..Wow this question is just terrible haha, probably really simple as well, I just don't get it.. T_T

and...another question...

Find the values of k, where k is a positive real number, for whic the equation 3 - ke^x - e^-x = 0 has one more solutions for x

3 - ke^x - e^-x = 0
=> 3e^x-ke^(2x) -1=0
Let e^x=a
Solve 3a-ka^2-1=0 by using quadratic formula

Do you mean one or more solution or more than one solution?
If one or more sol, let delta>=0, if more than one solution, delta>0

Sorry, I meant one or more, so do you have to solve using the quadractic formula? Or do you just use the discriminant thing? And also in this case would it be...a = 3 b= -k c= -1
or do you leave out the signs

You use discriminant>=0 only because they ask about value of k so no need to find x value I think
Discriminant= 9-4(-k)(-1) >=0 then solve for k