My Answers to Exam 2

[oneoneoneone]

It is definitely a general solution rather than two specific values.

[pi]

Check this too http://www.itute.com/board/viewtopic.php?f=3&t=2496

[InsaneMcFries]

OK Thanks for clearing that up.

[CCCCrystal]

crap i got the general solution but i crossed it out and put down 6 and -6 instead..... but why not? i dont think mine is wrong though.

[Imsobored]

If you said for that complex ques

npi/12=k x  pi/2
N= 6k k€J or n= + or -6, + or -18.....
Is it wrong?

[vcestudent94]

How much marks would I lose for the last question of the complex (If it was a 2 mark question I cant remember though) If I left it as z1=i*sin(pi/12*(12k-6)) , k E Z?
Would I get no marks?

[petal94]

crap i got the general solution but i crossed it out and put down 6 and -6 instead..... but why not? i dont think mine is wrong though.

That's what I did too! But the question didn't restrict the argument, so I think we were meant to keep the general solutions

Does anyone remember whether the question in 2. e ii said to express the solutions in Cartesian form, so i and -i, or would it be okay if we left it in polar form?

[datfatcat]

It is definitely a general solution rather than two specific values.

But the question is saying finding the value(s) of n.  General solution is not "values". but "solution"

[jaydee]

for q2eii i had i sin(kpi - pi/2) where kEZ which still yields the +/- i am i still technically right? :/

[datfatcat]

It is definitely a general solution rather than two specific values.

But the question is saying finding the value(s) of n.  General solution is not "values". but "solution"

What?
Infinite solutions is still value(s)
Anyway there's no way you can possibly justify non general with a dubious techinicality...
It's clearly a general solution, there's not even a debate about it...

How many marks would I lose for not giving general solution then? 1? 2?

[datfatcat]

Exam 1 30/40
Exam 2 70/80
SS 37?

[vcestudent94]

for q2eii i had i sin(kpi - pi/2) where kEZ which still yields the +/- i am i still technically right? :/

Yeah mines similar to yours I got:
i*sin(pi/2*(2k-1)), kEZ

Is mine techniquely right aswell?

[pi]

Exam 1 30/40
Exam 2 70/80
SS 37?

Depends on the exam 2 cut, but 37 sounds about right (if not a little lower).