So, the question is:
Chromate and dichromate ions form an equilibrium according to the following equation.
2CrO4(^2-) + 2H(^+) <--> Cr2O7(^2-) + H2O
Which solution would increase the concentration of the chromate ion (CrO4(^2-)) when added to the equilibrium mixture?
(A) Sodium nitrate
(B) Sodium chloride
(C) Sodium acetate
(D) Ammonium chloride
The answer is C.
My Working:
To get more Chromate ion (i.e. to shift equilibrium to the left) we'd need to add something that changes the concentration on the right side.
From above, that is Cr2O7(^2-) + H2O
A) NaNO3
B) NaCl
C) CH3COONa
D) NH4Cl
I took it that the amount of Na, N and Cl is redundant, as they aren't in the equation, removing option B.
(This is where I got stuck and guessed an answer)
Knowing the answer is C, I now assume that it's because it's the only one that has both H and O, increasing the amount of those two elements on the right side (which doesn't really sit well for my logic at the moment, as I believe it should be in the water format for this to work).
Please point out the flaws in my working, and help me understand why the answer is C
Thanks