Q5 e)... Why is electrolyzing a dilute aqueous solution of NACL a more effiecient way to produce hydrogen than electrolyzing water??
could this mean that nacl is more concentrated thus electrolyzing would be more effiecient???
Having electrolytes in the solution allows a faster movement of charge in the solution, in a way having a 'supercharged' salt bridge. Remember that the rate of electron transfer (the current) is limited by the slowest chain in the system. Having pure water, with a total ion concentration of

at 25 degrees, it is a very poor conductor and the motion of electrons will be restricted by this.
Q4b) " the acid -base indicator bromphenol blue is an equilibrium mixture of a weak acid and its conjugate base. The equilibrium may be represented by the equation...........HIn + H20 _arrow____ H3o + IN...... at What PH will the ratio [HIn]/[In] in bromphenol blue be 100/1?"
the answer replaces the HIn to 100 and In to 1 in the Ka formulae.. why do they do this?
Since it is given as a ratio, the units and relative magnitude cancels out. Substituting [HIn] = 1 and [In] = 0.01 will yield the same result, as the ratio is the same. Substituting [HIn] = 0.1 and [In] = 1*10^-3 will also yield the same result. Etc.
The simplest thing is to substitute the ratio itself in.
Q6e).... " Why is that copper can be produced by the electrolysis of an aqueous solution of Cu2+ ions, but lithium can not be produced by the electrolysis of an aqueous solution of Li + ions?
isn't H20 a stronger oxidant than cu2+??? however the answer says that h20 is below cu2+ thus Cu is stronger
Oxidant strength is on the left, where the stronger oxidant is found towards the top. The equation for oxidation of water (water is on the left hand side by itself with electron) is below Cu2+, and above Li+