Login

Welcome, Guest. Please login or register.

October 01, 2025, 05:08:52 pm

Author Topic: Core question 8  (Read 4178 times)  Share 

0 Members and 1 Guest are viewing this topic.

mirra250

  • Victorian
  • Trailblazer
  • *
  • Posts: 36
Re: Core question 8
« Reply #15 on: November 02, 2009, 11:46:36 pm »
the percentage of animals whose exposure to danger is high AND (key word being "and") whose chance of attack is below average is closest to 28%. thus the answer being C. you must consider there are two other loads of information. the AND gives this away. I am fairly confident with this, but chances are they will just give both correct anyway. way tooooo ambiguous
i'm sorry but if the "key word" was not AND but was OR, the question would not make sense! The word used has to be 'and'. But, I too do agree that the question is very ambiguous.

ashok

  • Victorian
  • Adventurer
  • *
  • Posts: 15
Re: Core question 8
« Reply #16 on: November 03, 2009, 10:20:42 am »
Firstly if you use the method High Exposure intersect below avg, the answer would be 29. C=28
Secondly, you dont know how many animals are in each group. Only percentages. So low exposure may have 10 animals while High has 100. So you cant assume that each group is equal making 29% incorrect.

E.G. 100 in high
       10 in low
        10 in medium

86 in high are below avg.
so 86/(100+10+10) *100 = 72 %

Any number of combinations depending on the numbers in each group.

So answer must be E
« Last Edit: November 03, 2009, 10:50:14 am by ashok »
2008 - Biology
2009 - Further Maths, Maths Methods, Accounting, Chemistry and English