Author Topic: Mav 2006 Question (Read 883 times) Tweet Share

naved_s9994 · « **on:** November 04, 2009, 07:54:04 am »

I can get to this part (attached), but if you read the question it asks to write it in another form.
Can anyone show me how to?

Thanks.

cobby · « **Reply #1 on:** November 04, 2009, 08:23:19 am »

$\frac {6e^{3x} \sqrt{x+1} - \frac {1}{2 \sqrt{x+1}} 2e^3x}{x+1}$

Multiplying $\frac {1}{2 \sqrt{x+1}} (2e^3x)}$ out gives: $\frac {e^3x}{ \sqrt {x+1}}$

Subbing back into original equation yields:
$\frac {6e^{3x} \sqrt {x+1} - e^{3x}}{(x+1)*\sqrt{x+1}}$

$\frac {6e^{3x} (x+1) - 3e^{3x}}{(x+1)^{3/2}}$

$\frac {6(x+1)e^{3x} - e^{3x}}{(x+1)^{3/2}}$

$\implies \frac{(6x+5)e^{3x}}{(x+1)^{3/2}}$

I did this in a hurry, so let me know if I've missed anything...

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Author Topic: Mav 2006 Question (Read 883 times) Tweet Share

naved_s9994

Mav 2006 Question

cobby

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